combined mass of the package and the sled? (Assume there is no friction.)
You pull a sled with a package on it across a snow-covered flat lawn. If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
The given data to find Mass,
The force applied to the sled, F = 65.1 N
Acceleration of the sled, a = 1.24 m/s²
Forces are defined by both strength and direction.
Force is a vector quantity. It is a quantity that is described by Magnitude and Direction. The strength of a force is its magnitude and the direction, well it is the direction the magnitude is applied on the object.
We need to find the combined mass of the package and the sled. Let it is m. Using definition of force as follows :
F = ma
m = F/a
m = 65.1 /1.24
Mass, m = 52.5 Kg.
If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
Hence, Option C is the correct answer.
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Answer:52.5
Explanation:
velocity
O acceleration
O inertia
O force
A net force of 6.8 N accelerates a 31 kaccontor
Answer:
O inertia
Explanation:
The tendency of a body to maintain its state of motion is inertia.
Inertia is the tendency of a body to remain at rest or in constant motion.
The tendency of an object to maintain its state of motion is known as inertia. It's a concept based on Newton's First Law of Motion
The tendency of an object to maintain its state of motion is called inertia. This is a fundamental concept in physics, based on Newton's First Law of Motion, which states that an object will remain at rest or move in a straight line at a constant speed unless acted upon by a net external force. While velocity, acceleration, and force are also involved in motion, inertia specifically is the property that defines an object's resistance to any change in its movement.
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Answer:
A generator produces electricity when a conducting wire is rotated between magnetic field. Mechanical energy is converted to electrical energy. Fleming's right hand rule is used.
An electric motor does mechanical work using electrical energy. A current carrying coil is placed in magnetic field. A torque is exerted on the coil and it rotates. Electrical energy is converted to mechanical energy. Fleming's left hand rule is used.
To calculate the volume of a cylindrical water tank, you can use the formula for the volume of a cylinder:
Volume = π * r^2 * h
Where:
- π (pi) is approximately 3.14159
- r is the radius of the cylinder
- h is the height of the cylinder
In this case, the radius (r) is 3 yards, and the height (h) is 7.5 yards. Plug these values into the formula:
Volume = π * (3 yards)^2 * 7.5 yards
Volume ≈ 3.14159 * (9 square yards) * 7.5 yards
Now, calculate the volume:
Volume ≈ 3.14159 * 67.5 cubic yards
Volume ≈ 212.05325 cubic yards
So, the volume of the cylindrical water tank is approximately 212.05 cubic yards.
Answer:4500 N
Explanation:
Given
mass of truck
mass of car
as the car push the ground with a force of 4500 N so the force on the truck should also be 4500 N as they all the force is transmitted to push the truck
and their acceleration is
Based on Newton's third law of motion, if the car is pushing against the ground with a force of 4500N, that same force is what propels the car and any object attached to it, regardless of the object's mass. Therefore, the car also applies a force of 4500N to the truck it is pushing.
The magnitude of force that a 1200-kg car applies to a 2100-kg truck with a dead battery can be calculated using the principles of Newtons's third law of motion which states that for every action there is an equal and opposite reaction. The force exerted by the car on the ground is equal to the force exerted by the ground on the vehicle. If the car's driving force against the ground is 4500N, as per Newton's third law, the ground also pushes the car back with the same force of 4500N. This force is what propels the car and any object it's connected with.
So, when the car is pushing this truck, it applies this same force of 4500N to the truck. Therefore, the magnitude of force the car applies to the truck is 4500N.
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