a machine uses 2.5 liters of fuel each hour it runs,its fuel tank was filled with 10 L but 1.5 L have already been used how
many more hours will the machine run

Answers

Answer 1

Answer:

The number of hours machine runs with 8.5 L fuel is 3.4 hours.

Given that, a machine uses 2.5 liters of fuel each hour it runs, its fuel tank was filled with 10 L but 1.5 L have already been used.

What is the unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Now, 10 - 1.5 = 8.5 L

So, the number of hours = 8.5/2.5

= 3.4 hours

Therefore, the number of hours machine runs with 8.5 L fuel is 3.4 hours.

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Answer 2

Answer: 10-1.5=8.5
8.5/2.5= 3.4 hours

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PM is the median of trapezoids klno.

Answers

Answer:

Step-by-step explanation:

i dont get it

i cant figure it out Step-by-step explanation:

Which of the following is an arithmetic sequence?2, 4, 8, 16,...
12, 4, 4/3, 16/3...
1/2, -1/2, -3/2, -5/2 ...
1/2, -1/2, 1/2, -1/2 ...

Answers

Answer:

The third sequence.

Step-by-step explanation:

In an arithmetic sequence, the difference between two consecutive terms is the same.

For each option, find the difference between consecutive terms:

First option:

$4 - 2 = 2$ .
$8 - 4 = 4$ .
$16 - 8 = 8$ .

The differences are not the same. As a result, this option is not an arithmetic sequence.

Second option:

$4 - 12 = -8$ .
$\displaystyle (4)/(3) - 4 = -(8)/(3)$ .
$\displaystyle (16)/(3) - (4)/(3) = (12)/(3) = 4$ .

The differences are not the same. As a result, this option is not an arithmetic sequence, either.

Third option:

$\displaystyle -(1)/(2) - (1)/(2) = -1$ .
$\displaystyle -(3)/(2) - \left(-(1)/(2)\right) = -(3)/(2) + (1)/(2) = -1$ .
$\displaystyle -(5)/(2) - \left(-(3)/(2)\right) = -(5)/(2) + (3)/(2) = -1$ .

The differences are all $-1$ . As a result, this option is indeed an arithmetic sequence. Its common difference is $(-1)$ .

Fourth option:

$\displaystyle -(1)/(2) - (1)/(2) = -1$ .
$\displaystyle (1)/(2) - \left(-(1)/(2)\right) = (1)/(2) + (1)/(2) = 1$ .
$\displaystyle -(1)/(2)\right - (1)/(2) = -1$ .

The differences are varying between $1$ and $-1$ . As a result, this option is not an arithmetic sequence.

Answer: Number 3. (1/2, -1/2, -3/2, -5/2 ...)

Step-by-step explanation:

1/2 - 1 = -1/2. -1/2 - 1 = -3/2. Etc.

The answer. what is the prime factorization of 801

Answers

Simple,

C.

The prime factorization of 801 is.... 3*3*89, or $3^(2) *89$

Thus, your answer.

Final answer:

The prime factorization of 801 is 3 * 3 * 89.

Explanation:

The prime factorization of 801 is 3 * 3 * 89.

To find the prime factorization of 801, we can start by factoring out the smallest prime number, which is 3. Dividing 801 by 3 gives us 267. Next, we continue factoring each subsequent quotient until we reach 1. Dividing 267 by 3 gives us 89, which is a prime number. Therefore, the prime factorization of 801 is 3 * 3 * 89.

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Please Help me with #1thanks

Answers

Brad needs (30.1 + 37.5 + 14.8 + 10.01 + 15.2) = 107.61 cm of wood.

How many lengths does he need in order to have 107.61 cm of wood ?

(107.61 cm) / (35 cm/length) = 3.075 lengths

3 lengths is not quite enough. But it's only sold in whole lengths of 35 cm.
So in order to cover that last little smidgen, he'll need to buy 4 lengths.

How many times larger is 9 x 10^-4 than 3 x 10^-10? A) 3 x 105
B) 3 x 106
C) 6 x 105
D) 6 x 106

Answers

9 x 10^-4: Since the exponent of the scientific notation is negative −4, move the decimal point 4 places to the left. Answer: 0.0009

3 x 10^-10: Since the exponent of the scientific notation is negative −10, move the decimal point 10 places to the left. Answer: 0.0000000003

Subtract: C) 6 x 105

The national catch of Atlantic Cod has been declining in the past few decades. We can model this decline with the equation y = −.003x2 + .120x + 1.909 where x is the number of years since 1950 and y is the catch in millions of metric tons. In which year did the catch reach its maximum? In which year will the catch reach 0? For what years was the catch increasing? Decreasing? When was the catch greater than 2.5 million metric tons? Show all of your work or explain how you came up with your solutions.

Answers

y = -.003x² + .120x + 1.909
Standard form of a parabola is y = ax² + bx + c. The x coordinate of the vertex can be found with -b/2a.
-.120/(2 × -.003) + 20
So the max is at 1950 + 20 because x is years after 1950. Which is 1970.
To find when y will be 0, use the quadratic equation x = [-b +/- √(a² - 4ac)]/2a. +/- means plus or minus because I can't type the actual symbol.
x = [-.120 +/- √(-.003² - 4(-.003)(1.909))]/2(-.003) Plug in info
x = [-.120 +/- √(.000009 - 4(-.005727))]/-.006
x = [-.120 +/- √(.000009 + .022908)]/-.006
x = [-.120 +/- √(.022917)]/-.006
x=-.120/-.006 +/- √(.022917)/-.006
x = 20 +/- .15138361866/-.006
x = 20 +/- -25.2306031108
Because it is plus or minus you split it and do both.
x = 20 - -25.2306031108 x = 20 + -25.2306031108
x = 45.2306031108 x = -5.23060311077
so y is 0 when x is 45.2306031108 because there is no such thing as negative time so it can't be the other one. So the answer is 1995 because you add 45 to 1950.
Since the max is at 1970, it is increasing from 1950 to 1975 and decreasing from 1975 to 1995.

Sorry I took so long, I had to look up how to do it because I couldn't remember.

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