To find how much water was in the pool originally, you need to write the function for how fast the water is leaving the pool.
Your function is
y=-8x+b
y is amount of water in the pool
x is how many hours
b is the original amount
Since you know y and x, plug those into the function.
132=-8(6)+b
132=-48+b
b=180
The original amount of water in the pool was 180 gallons.
I didn't mean to reanswer the question, I'm sorry! I didn't see that there was already an answer when I began answering.
Obtuse
Acute
Supplementary
Right
Please help!!!?!!
Option D:
Right triangle
Solution:
Let us first define obtuse, acute right triangle and supplementary.
Obtuse angled triangle:
If any one of the angle in the triangle is more than 90°, then the triangle is an obtuse angled triangle.
Acute angled triangle:
If all the angles of the triangle are less than 90°, then the triangle is an acute angled triangle.
Right angled triangle:
If any one of the angle in the triangle is exactly 90°, then the triangle is a right angled triangle.
Supplementary:
If sum of the angles is 180°, then the angles are supplementary angles.
But this is not a kind of triangle.
In given triangle one of the angle is 90°.
Therefore, this is a kind of right triangle.
Option D is the correct answer.
b) x= -0.4
c) x=2.5
d) x= -2.5
Answer:
a)x=0.4
Step-by-step explanation:
-0.5-3.69=x-1.9-2.39
-3.69+1.9+2.39=x+0.5x
-3.69+4.29=1.5x
0.6=1.5x
x=0.6/1.5
x=0.4
Transpose the values
Evaluate
or
Answer: a)
Answer:
-16 - 30i
Step-by-step explanation:
(3-5i)^2 = (3-5i) * (3-5i)
Applying the "FOIL" method of expanding this expression through multiplication, we get:
9 - 15i - 15i - 25 (since i^2 = -1)
Simplifying this result, we get -16 - 30i