Final answer:
The problem can be solved by setting up and solving an equation based on the number of coins - specifically dimes and pennies. After Peter spends some of his dimes, the remaining dimes are half the number of his pennies. From this, we can find out that Peter has 12 pennies.
The subject of this question is Mathematics, specifically, it focuses on solving word problems, and in this case, the problem relates to coins - dimes and pennies. From the problem, we know that Peter starts with 18 dimes and he spends 12 dimes, he will be left with 18 - 12 = 6 dimes.
The problem also states that the number of pennies Peter has is twice the number of dimes. Therefore, we can write this as an equation: 2 × (Number of dimes) = Number of Pennies.
Substituting the number of dimes (6), the equation become: 2 × 6 = Number of Pennies. Solving this equation, Peter has 2 × 6=12 pennies.
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A12 over a7
Answer:
a^5.
Step-by-step explanation:
a^12 / a^7 = a^(12 - 7) = a^5.
Hope this helps!
The equation of the line x + 2y = 6 in slope-intercept form is y = - (1/2)x + 6.
The slope is the rate of change of the y-axis with respect to the x-axis.
The equation of a line in slope-intercept form is y = mx + b, where
slope = m and y-intercept = b.
We know the greater the absolute value of a slope is the more steeper is its graph or the rate of change is large.
The equation of the given line is x + 2y = 6.
We know equation of a line in slope intercept form is,
y = mx + b.
Therefore,
x + 2y = 6.
2y = - x + 6.
y = - (1/2)x + 6.
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Answer:
y= -1/2x+3
Step-by-step explanation:
The simplified form of the fraction 31/33 is 31/33.
An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.
Given:
A fraction,
31/33.
A fraction that can not be factorized further is the simplest form of the fraction.
31 and 33 both numbers do not have a common divisor other than 1.
Therefore, 31/33 is in the simplest form.
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equations and get the letters to decode the hidden message . You
may use the extracting the square root method
P:±6
M: ±7
C:5,6
A : 0
J:4,-1
Q:±√5
L:±11
H:±4
D:-4,1 I:±3
S:16,-6
Y: ±8
B:±4√2
E:±2
A:0,-4
U:6,0
U:±√10
N:6,-16
G:1,-1
T:±2√2
O:±6√2
V:±√3
I:±5
J:-7,-1
K:5,-2
W:±12
F:±2√3
X:±6
R:0,-6
•:9±√6
/4
Message : __________________________________
________________________________________
1. x2 = 49
2. x2 -27 =0
3. 3x2-36= 0
4. 9x2 = 0
5. 5x2- 15=0
6. 2x2- 144=0
7. ( x + 3)2 = 9
8. 4x2 -100 =0
9. 5x2 = 40
10. 3x2 -12 = 0
11. (x-5)2
The corresponding roots of the quadratic equations are given.
Quadratic expressions are polynomial equations of second degree.
The general form of a quadratic equation is ax² + b x + c = 0.
1. x² = 49
Find the square root.
x = ±√49 = ±7
2. x² - 27 = 0
x² = 27 = 9 × 3
x = √27 = √(9×3) = √9 × √3 = ±3√3
3. 3x² - 36 = 0
3x² = 36
Divide 3 on both sides.
x² = 12
x = √12 = √(4 × 3) = ±2√3
4. 9x² = 0
x = 0
5. 5x² - 15 = 0
5x² = 15
x² = 3
x = ±√3
6. 2x² - 144 = 0
2x² = 144
x² = 72
x = √72 = √(36 × 2) = ±6√2
7. (x + 3)² = 9
x + 3 = √9
x + 3 = ±3
x = 3 - 3 = 0 and x = -3 - 3 = -6
8. 4x² - 100 = 0
4x² = 100
x² = 25
x = ±√5
9. 5x² = 40
x² = 8
x = √8 = √(4 × 2) = ±2√2
10. 3x² - 12 = 0
3x² = 12
x² = 4
x = ±2
11. (x - 5)² = 121
x - 5 = √121
x - 5 = ±11
x = 11 + 5 = 16 or x = -11 + 5 = -6
Hence the solutions are found.
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