How do I factor this polynomial? q^2-121

Answers

Answer 1

Answer: $q^2-121 =q^2-11^2=(q-11)(q+11)\n \n \na^2-b^2 =(a-b)(a+b)$

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Which property is BEST to use when simplifying (0.58+0.32)+ 0.68

Answers

i don’t know but i hope u find the answer

The mean of a population being sampled is 64, and and the standard deviation is 6. If the sample size is 50, the standard error of the mean is . (Round off your answer to the nearest hundredth.)

Answers

Given:
mean = 64
standard deviation = 6
sample size = 50

Standard error of the sample mean = standard deviation / √sample size

Standard error = 6 / √50 = 6/7.07 = 0.85

Answer:

See image

Step-by-step explanation:

Plato

What is the value of y so that the ordered pair (5, y) is a solution to the equation –5x + y = –40?A.
–65

B.
9

C.
–15

D.
7

Answers

$-5x + y = -40\n\nx=5\n\n-5(5)+y=-40\n-25+y=-40\ny-25 = -40\ny -25+ 25 = -40+25\ny = -40+25\n\n\boxed{\bf{y=-15}}$

Answer is C.

How do i derive (x^-4) using the limit definition [f(x+h) - f(x) / h]

Answers

$f'(x)=\lim\limits_(h\to0)(f(x-h)-f(x))/(h)\n\nf(x)=x^(-4)=(1)/(x^4)\n\nf'(x)=\lim\limits_(h\to0)((x+h)^(-4)-x^(-4))/(h)=\lim\limits_(h\to0)((1)/((x+h)^4)-(1)/(x^4))/(h)=\lim\limits_(h\to0)((x^4-(x+h)^4)/(x^4(x+h)^4))/(h)\n\n=\lim\limits_(h\to0)\left[(x^4-x^4-4x^3h-6x^2h^2-4xh^3-h^4)/(x^4(x+h)^4)\cdot(1)/(h)\right]=\lim\limits_(h\to0)(-4x^3h-6x^2h^2-4xh^3-h^4)/(hx^4(x+h)^4)$

$=\lim\limits_(h\to0)(h(-4x^3-6x^2h-4xh^2-h^3))/(hx^4(x+h)^4)=\lim\limits_(h\to0)(-4x^3-6x^2h-4xh^2-h^3)/(x^4(x+h)^4)\n\n=(-4x^3-6x^2\cdot0-4x\cdot0^2-0^3)/(x^4(x+0)^4)=(-4x^3)/(x^4\cdot x^4)=(-4)/(x^5)\n\n\nD_f=D_(f')=\mathbb{R}\ \backslash\ \{0\}$

A cube has an edge measuring 4 inches. What is the surface area of the cube, in inches²?