Ans: Volume of stock H2SO4 required = 6.94 ml
Given:
Concentration of stock H2SO4 solution M1 = 18.0 M
Concentration of the final H2SO4 solution needed M2 = 2.50 M
Final volume of H2SO4 needed, V2 = 50.0 ml
To determine:
Volume of stock needed, V1
Explanation:
Use the dilution relation:
Hello!
In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?
We have the following data:
M1 (initial molarity) = 2.50 M (or mol/L)
V1 (initial volume) = 50.0 mL → 0.05 L
M2 (final molarity) = 18.0 M (or mol/L)
V2 (final volume) = ? (in mL)
Let's use the formula of dilution and molarity, so we have:
Answer:
The volume is approximately 6.94 mL
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Most of the positively charged particles should bounce back at a range of angles as they collide with the atoms in the foil; only a few should pass straight through the foil.
The Gibbs free energy change for this reaction at 298 K is approximately -54,484.8 J.
Calculating the Gibbs free energy change (ΔG) for a reaction at a given temperature using the Gibbs-Helmholtz equation,
ΔG = ΔH - TΔS
ΔG = (-144,600 J) - (298 K)(-301.2 J/K)
ΔG = -144,600 J + 90,115.2 J
ΔG = -54,484.8 J
ΔG = -54,484.8 J
Converting to kilojoules:
ΔG = -54,484.8 J / 1,000
= -54.48 kJ
Learn more on Gibbs free energy change here brainly.com/question/13765848
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Balance the equation and state which substance is oxidised and which is reduced
Explanation:
To balance the chemical equation for the extraction of iron from iron(III) oxide using carbon, you need to ensure that the same number of each type of atom appears on both sides of the equation. Here's the balanced equation:
2Fe₂O₃ + 3C -> 4Fe + 3CO
Now, let's determine which substance is oxidized and which is reduced:
1. Iron (Fe) undergoes a change in oxidation state from +3 in iron(III) oxide (Fe₂O₃) to 0 in elemental iron (Fe). It is reduced because it gains electrons, going from a higher positive oxidation state to zero.
2. Carbon (C) in carbon (C) undergoes a change in oxidation state from 0 to +2 in carbon monoxide (CO). Carbon is oxidized because it loses electrons and goes from an oxidation state of 0 to +2.
So, in this chemical reaction:
- Iron is reduced (it gains electrons).
- Carbon is oxidized (it loses electrons).