The composite number sought is 12250 which is greater than 1000. Its prime factorization includes the prime numbers 2 (that does not repeat), 5 (that repeats thrice), and 7 (that repeats twice).
The subject is looking for a composite number greater than 1000, whose prime factorization contains 3 types of prime numbers: one that does not repeat, the second repeats three times, and the third repeats twice. We have many prime numbers but to get a number greater than 1000, let’s use larger prime numbers for instance 2, 5 and 7. Let's calculate the composite number with these primes:
2^1 * 5^3 * 7^2 = 2 * 125 * 49 = 12250
Therefore, 12250 is a composite number greater than 1000 whose prime factorization contains 1 prime number(2) that does not repeat, 1 prime number(5) that repeats three times and 1 prime number(7) that repeats twice.
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We are given that a total of 100 digital video recorders (DVRs) out of these 14 are defective.
The probability of randomlyselect an item that is defective,
P(A) = n(A)/n(S)
P(A) = 14/100
P(A) = 7/50
The probability of randomlyselecting an item that is not defective,
P(A) = 1-(7/50)
P(A) = (50-7)/50
P(A) = 43/50
Hence, the probability of randomly selecting an item that is not defective is 43/50.
Learn more about probability at brainly.com/question/10720683
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Answer:
1200 ÷ 4 = 300
Step-by-step explanation: