PLEASE HELP NEED TO PASS!!!!!!!!The graph shows the relationship between the number of ounces of cereal in a box and the price of the cereal. What is the correlation between the weight and price of a box of cereal? none positive negative constantnone
positive
negative
constant
PLEASE HELP NEED TO PASS!!!!!!!!The graph shows the relationship between - 1

Answers

Answer 1
Answer:

For this case, the first thing we must do is observe the relationship between the variables:

Independent variable: Weight of the box (ounces)

Dependent variable: Price of the box ($)

Observing the behavior between both variables, we see that there is no specific relationship between the increase or decrease in the weight of the box and the increase or decrease in the price.

Therefore, there is no correlation between the variables.

Answer:

the correlation between the weight and price of a box of cereal is:

none

Answer 2
Answer:

The graph does not show a trendline, therefore, the correlation between the weight and price of a box of cereal is: none.

Correlation Relationship between Two Variables

  • If two variables are correlated, it means an increase in one affects the other and vice versa.
  • On a scatter plot, a if all the data points are along a straight-line or form a trendline, it shows a correlation relationship between two variables.

Thus, the graph does not show a trendline, therefore, the correlation between the weight and price of a box of cereal is: none.

Learn more about correlation relationship on:

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The running time for movie A is 33 mins more than twice the running time for movie B. If the running time for movie A is subtracted from triple the running time for movie B, the result is 57 mins. find the running time for each movie..Movie A- Movie B-

What is the slope-intercept form equation of the line that passes through (2, 4) and (4, 10)?

Answers

x_(1)=2\ny_1=4\nx_2=4\ny_2=10
equation of the line passes through two points:
(x_2-x_1)(y-y_1)=(y_2-y_1)(x-x_1)\n(4-2)(y-4)=(10-4)(x-2)\n2y-8=6x-12\n2y=6x-4\ny=3x-2
the slope is \frac {10-4}{4-2} = 3 and thus our equation becomes y-4=3*(x-2).
If we rearrange terms we get y=3x-2

jens motorboat travels at a speed of 15mph in still water, the river flows at a speed of 2pmh, how long will it take jen to travel 20mi upstream? 20mi downstream?

Answers

The speed of the motorboat travelling up stream will be 13mph, therefore it will take 20/13 hours to travel 20 miles upstream. This is about 1 and a half hours. The speed of the motorboat travelling downstream will be 17mph, therefore it will take 20/17 hours to travel 20 miles downstream. This is about 1 hour 10 minutes.

2(X+3)=x-4 and 4(5x-2)=2(9x+3)​

Answers

Answer:

2x+10=x and 2x=14 this is what I got

Step-by-step explanation:

+

(4x4 + 3x3 +2x + 1)/ (x2 + x+2)

Answers

4x^2 - x - 7
x^2 + x + 2|4x^4 + 3x^3 + 0x^2 + 2x + 1
- (4x^4 + 4x^3 + 8x^2)
-x^3 - 8x^2 + 2x
- (-x^3 - x^2 - 2x)
-7x^2 + 0x + 1
- (-7x^2 - 7x - 14)
7x + 15

It is equal to 4x^2 - x - 7 + ((7x + 15)/(x^2 + x + 2)).

Find the three cube roots of the complex number 8i. Give your answers in the form x + iy

Answers

8i is:
 z = 8(cos(90) + i sin(90)) ; now take the 1/3 power of it.

When we take this to a normal integer power of 3 we get:

z^3 = 8^3(cos(90*3) + i sin(90*3)) right? its the same for rational exponents as well.

z^(1/3) - 2(cos(90/3) + i sin(90/3))

90/3 = 30; the cos(30)=sqrt(3)/2 and the sin(30) = 1/22(sqrt(3)/2 + i 1/2) = sqrt(3) + 1i should be one of the cube roots.

(sqrt(3) + i)^2 = 2 +2sqrt(3) i
(sqrt(3)+i) (2 +2sqrt(3)i
2sqrt(3) + 6i +2i -2sqrt(3) = 8i

Let $A = (5,12)$, $B = (0,0)$, and $C = (14,0)$. For a point $P$ in the plane, the minimum value of $PA^2 + PB^2 + PC^2$ can be expressed in the form $m/n$, where $m$ and $n$ are relatively prime positive integers. Find $m + n$.

Answers

Answer:

45

Step-by-step explanation:

do it

To find the minimum value of the sum of the squares of distances, we can use calculus. The minimum value can be expressed as $233/9$.

To find the minimum value of $PA^2 + PB^2 + PC^2$, we need to find the point $P$ that minimizes the sum of the squares of the distances from $P$ to $A$, $B$, and $C$. Let's denote the coordinates of $P$ as $(x, y)$. Using the distance formula, we can find the expressions for the squares of the distances:




  1.  
  2. $PA^2 = (x - 5)^2 + (y - 12)^2$

  3.  
  4. $PB^2 = x^2 + y^2$

  5.  
  6. $PC^2 = (x - 14)^2 + y^2$



The sum of these expressions is $PA^2 + PB^2 + PC^2$:



$PA^2 + PB^2 + PC^2 = (x - 5)^2 + (y - 12)^2 + x^2 + y^2 + (x - 14)^2 + y^2$



Simplifying the expression:



$PA^2 + PB^2 + PC^2 = 3x^2 + 3y^2 - 38x - 24y + 365$



To find the minimum value, we can use calculus. Taking the partial derivatives of this expression with respect to $x$ and $y$ and setting them to zero, we can find the critical points. The coordinates of the point $P$ that minimizes the sum of the squares of the distances are $(x, y) = (13/3, 8/3)$. Plugging these values into the expression, we get:



$PA^2 + PB^2 + PC^2 = (13/3)^2 + (8/3)^2 = 233/9$



Therefore, the minimum value can be expressed as $233/9$, and $m + n = 233 + 9 = 242$.

Learn more about Sum of squares of distances here:

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