The prism has a surface area of 202 ft2.What would the surface area of the prism be if each dimension were tripled?



ft2

Answers

Answer 1
Answer: Let's call the dimensions of the prism (I will assume it is rectangular) a, b, and c.

The surface area is:

2ab + 2ac + 2bc = 202

The dimensions of the new prism are 3a, 3b, and 3c.

This surface area would be:

2(3a)(3b) + 2(3a)(3c) + 2(3b)(3c) =

2(9ab) + 2(9ac) + 2(9bc) =

9(2ab + 2ac + 2bc) =

9(202) = \boxed{1818}

Hope this helps :D



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