b. Approximately 2758
c. Approximately 40
d. Approximately 70
The predicted value received on the exam when the percentage attendance is 70 is ( a. Approximately 63).
To find the predicted value of the exam score when the percentage attendance is 70, to use the regression equation provided:
Y = Intercept + Attendance × X
From the regression statistics that the intercept (Intercept) is 39.39027309 and the coefficient for percentage attendance (Attendance) is 0.340583573.
Substituting the values into the equation:
Predicted value = 39.39027309 + 0.340583573 × 70
Calculating:
Predicted value ≈ 39.39027309 + 23.84485711
Predicted value ≈ 63.2351302
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Answer:
c
Step-by-step explanation:
hope this helps hœ
show your work
Answer:
x ⥶ 8
Step-by-step explanation:
1/2x + 1 ⥶5
x + 2 ⥶ 10
x ⥶ 10 - 2
Which of these is logically equivalent to the given statement? (1 point)
1. If Amelia did not go to the park, then she did not finish her homework.
2. If Amelia did not finish her homework, then she will go to the park.
3. If Amelia goes to the park, then she did not finish her homework.
4. If Amelia finishes her homework, then she cannot go to the park.
Hello there.
In this problem, we can use our intuition of logic, but I will show a proof of the result in a truth table later. Then, let's get started!
Given:
→ Amelia finishes the homework (sentence H, can be True or False)
→ Amelia goes to the park (P, true or false)
Then, we have: If H, then P. Logically:
H ⇒ P
Then we can think: everytime she does the homework, she goes to the park. Therefore, if she did not go to the park, she will not have finished the homework (It is an equivalent sentence).
Alternative 1.
==========
Now, let's prove that (H ⇒P) is equivalent to (¬P ⇒ ¬H), via the truth table:
H P ¬H ¬P (H ⇒ P) (¬P ⇒ ¬H)
T T F F T T
T F F T F F
F T T F T T
F F T T T T
As we can see, the results are identical, therefore, the sentences are indeed equivalent.
I hope it hepls :)
3 cm
2 cm
3 cm
6 cm
Find the surface area of the above solid.
A. 81 cm2
B. 78 cm2
C. 84 cm2
D. 72 cm2
Answer:It’s C
Step-by-step explanation:
Notice that Given that is an ellipse, consider a conversion to polar coordinates:
The Jacobian for this transformation is
with determinant
Then the integral in polar coordinates is
where you can evaluate the remaining integral by substituting and .
To evaluate the integral, we make a change of variables using the transformation x=u/8 and y=v/9 to transform the region into a unit circle. Then we convert the integral to polar coordinates and evaluate it.
To evaluate the given integral, we can make the appropriate change of variables by using the transformation x = u/8 and y = v/9. This will transform the region R into a unit circle. The determinant of the Jacobian of the transformation is 1/72, which we will use to change the differential area element from dA to du dv. Substituting the new variables and limits of integration, the integral becomes:
L = \iint_{R} 9 \sin (612 u^{2} + 768 v^{2}) \cdot (1/72) \,du \,dv
Next, we can convert the integral from Cartesian coordinates(u, v) to polar coordinates (r, \theta). The integral can be rewritten as:
L = \int_{0}^{2\pi} \int_{0}^{1} 9 \sin (612 r^{2} \cos^{2}(\theta) + 768 r^{2} \sin^{2}(\theta)) \cdot (1/72) \cdot r \,dr \,d\theta
We can then evaluate this integral to find the value of L.
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