a-plus auto body is painting desings on a customer's car. they had 18 pints of blue paint on hand. they used 1/2 of it for the flames, and 1/3 of it for the sparks. they needed 7 3/4 pints of blue paint to paint the next design. how many more pints of blue paint will they need?

Answers

Answer 1
Answer:

The amount of more blue paint needed is 19 / 4 pints

They are painting a designs on a customer's car . They had 18 pints of blue paints on hand.

Amount used on flames = 1 / 2 pints

Amount used on spark = 1 / 3 pints

Therefore,

Total pints used:

  • 1 / 2 + 1 / 3 = 5 / 6

Therefore,

5 / 6 of 18 = 5  / 6 × 18 = 15 pints

Therefore, 15 pints of the paint has been used. The remaining pints of paint is 18 - 15 = 3 pints of paints.

They needed 7 3 / 4 pints of paints.

7 3 / 4 = 31 / 4 pints

Amount needed = 31 / 4  - 3 = 31 - 12/ 4 = 19 / 4 pints of paints

learn more algebra here: brainly.com/question/239042

Answer 2
Answer:

4³/₄ pints

Further explanation

Given:

A-Plus auto body is painting desigs on a customer's car.

  • They had 18 pints of blue paint on hand.
  • They used (1)/(2) of it for the flames, and (1)/(3) of it for the sparks.
  • They needed 7(3)/(4) pints of blue paint to paint the next design.

Question:

How many more pints of blue paint will they need?

The Process:

From the denominators 2 and 3 above, we get LCM = 6.

Let us draw a diagram that contains all the pints.

18 \ pints / 6 \ units = 3 \rightarrow \boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3} = 18 \ pints

The flames: (1)/(2) or half of 6 unit above, that is \boxed{3}\boxed{3}\boxed{3} = 9 \ pints

The sparks: (1)/(3) = (2)/(6) or 2 of 6 unit above, that is \boxed{3}\boxed{3} = 6 \ pints

So, the remainder is 18 - 9 - 6 = 3 pints.

They needed 7(3)/(4) pints of blue paint to paint the next design.

Let us count how many more pints of blue paint will they need.

\boxed{7(3)/(4) - 3 = ?}

\boxed{= \bigg( 7 + (3)/(4) \bigg) - 3}

\boxed{= 7 - 3 + (3)/(4)}

\boxed{\boxed{ \ 4(3)/(4)}}

Thus, they4(3)/(4)pints more of blue paint.

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Keywords: A-Plus, auto body, painting, designs, on a customer's car, they had 18 pints, blue paint, 1/2, for the flames, 1/3, the sparks, they needed, 7³/₄, the next design, how many more, will they need


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9+ (– 7) =

Answers

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Step-by-step explanation:

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Step-by-step explanation:

JK Fitness Center offers two membership plans. The tables represent the monthly cost, in dollars, of each membership plan based on thenumber of visits to the fitness center.
PART A: At a certain number of visits, both plans will cost the same. At that number, how much will both plans cost, in dollars?

PART B: Which plan is more expensive at the 10th visit?
Write the number of the plan in the box.

Answers

After 15 number of visits, both plans cost $55 and at the 10th visit, plan 2 is more expensive than plan 1.

What is Arithmetic Sequence?

Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.

Part A :

From the table, we can clearly express both plans as Arithmetic sequence.

Plan 1 : First term, a = 27 and common difference, d = 2

Plan 2 : First term, a = 41 and common difference, d = 1

Let n be the number of visits that both plans costs the same.

27 + 2(n - 1) = 41 + (n - 1)

27 + 2n - 2 = 41 + n - 1

2n + 25 = n + 40

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Cost = 41 + (15 - 1) = $55

Part B :

We have to find the 10th term.

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For plan 2 :

Cost at 10th visit = 41 + (10 - 1) = $50

The plan 2 is more expensive at the 10th visit.

Hence at the 10th visit, plan 2 is more expensive.

Learn more about Arithmetic Sequence here :

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Step-by-step explanation:

From the looks of it, Plan A is 25 + 2x and plan B is 40 + x.

Part A:

25 + 2x = 40 + x

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plug in any: 40 + 15 = $55

Part B:

Plan A = $45

Plan B = $50

Plan B is $5 more expensive.