The amount of more blue paint needed is 19 / 4 pints
They are painting a designs on a customer's car . They had 18 pints of blue paints on hand.
Amount used on flames = 1 / 2 pints
Amount used on spark = 1 / 3 pints
Therefore,
Therefore,
5 / 6 of 18 = 5 / 6 × 18 = 15 pints
Therefore, 15 pints of the paint has been used. The remaining pints of paint is 18 - 15 = 3 pints of paints.
They needed 7 3 / 4 pints of paints.
7 3 / 4 = 31 / 4 pints
Amount needed = 31 / 4 - 3 = 31 - 12/ 4 = 19 / 4 pints of paints
learn more algebra here: brainly.com/question/239042
4³/₄ pints
Given:
A-Plus auto body is painting desigs on a customer's car.
Question:
How many more pints of blue paint will they need?
The Process:
From the denominators 2 and 3 above, we get LCM = 6.
Let us draw a diagram that contains all the pints.
The flames: or half of 6 unit above, that is
The sparks: or 2 of 6 unit above, that is
So, the remainder is 18 - 9 - 6 = 3 pints.
They needed pints of blue paint to paint the next design.
Let us count how many more pints of blue paint will they need.
Thus, theypints more of blue paint.
Keywords: A-Plus, auto body, painting, designs, on a customer's car, they had 18 pints, blue paint, 1/2, for the flames, 1/3, the sparks, they needed, 7³/₄, the next design, how many more, will they need
On a coordinate plane, a rectangle is 5 units high and 7 units wide.
On a coordinate plane, a rectangle is 4 units high and 8 units wide.
On a coordinate plane, a rectangle is 6 units high and 8 units wide.
Answer: a :)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
9+ (– 7) =
Answer:
9+ (– 7) = 2
Step-by-step explanation:
Answer:
it = 2
Step-by-step explanation:
PART A: At a certain number of visits, both plans will cost the same. At that number, how much will both plans cost, in dollars?
PART B: Which plan is more expensive at the 10th visit?
Write the number of the plan in the box.
After 15 number of visits, both plans cost $55 and at the 10th visit, plan 2 is more expensive than plan 1.
Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.
Part A :
From the table, we can clearly express both plans as Arithmetic sequence.
Plan 1 : First term, a = 27 and common difference, d = 2
Plan 2 : First term, a = 41 and common difference, d = 1
Let n be the number of visits that both plans costs the same.
27 + 2(n - 1) = 41 + (n - 1)
27 + 2n - 2 = 41 + n - 1
2n + 25 = n + 40
n = 15
Cost = 41 + (15 - 1) = $55
Part B :
We have to find the 10th term.
For plan 1 :
Cost at 10th visit = 27 + 2(10 - 1) = $45
For plan 2 :
Cost at 10th visit = 41 + (10 - 1) = $50
The plan 2 is more expensive at the 10th visit.
Hence at the 10th visit, plan 2 is more expensive.
Learn more about Arithmetic Sequence here :
#SPJ3
Step-by-step explanation:
From the looks of it, Plan A is 25 + 2x and plan B is 40 + x.
Part A:
25 + 2x = 40 + x
x = 15
plug in any: 40 + 15 = $55
Part B:
Plan A = $45
Plan B = $50
Plan B is $5 more expensive.