The planet Mars could be a future destination for the U.S. space program. Assume that Mars is a perfect sphere. Its surface area is about 145 million square kilometers. What is the radius of Mars at its equator? Round to the hundreds place. ||| Answer choices: A) 4,500 km B) 2,200 km C) 5,000 km D) 3,400 km |||
Answers
Answer 1
Answer:
surface area of a sphere is 4 times pi timers radius^2 aprox pi=3.14
so surface area=145,000,000
145,000,000=4 times 3.14 times rdaius^2 145,000,000=12.56 times radius^2 divide both sdies by 12.56 11544585.987=r^2 square root both sides 3397.73=radius
round to the hundreds 3397 rounded to the hundreds 3400
A porch has the shape of a semicircle with a diameter of 7 ft.What is the approximate area of the porch, rounded to the nearest square foot? Use 3.14 to approximate .
ft2
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A = pi * r^2
R = D / 2
R = 7 / 2
R = 3.5
A = 3.14 * 3.5^2
A = 3.14 * 12.25
A = 38.465
Divide it by 2 since its a semi-circle:
38.465 / 2 = 19.2325
So about 19 square feet.
A = pi * r^2
A = 3.14 * 3.5^2
A = 38.465
38.465/2 = 19.2325 square feet of semicircle
It has 1 more vertex than an octagon and 2 fewer sides than a hendecagon
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The answer is a nonagon which has 9 sides which fits your description
25 points. Math question
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=> The answer is -8.
Answer:
-8
Step-by-step explanation:
I believe it is -8
first you 2(-2) - 4
then you -4 -4= -8
Hope that was helpful.
I dont get what to do
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I'm pretty sure you're just solving for x. For example, in 26. You have: x/18 = 4.5 You multiply both sides by 18 to get the x by itself x = 4.5 • 18 You simplify this x = 81
24. x= 15.625 26. x= 81 28. x= 980 30. x=2
What is the LCD of 3/10 and -4/15 ?
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The LCD of 3/10 and -4/15 is 30.
How can you contruct a triangle
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Well, I think you meant 'construct' and not 'contruct', but if you did mean 'contruct', then I can't help you. However, to construct a triangle all you need to do is use 3 straight line segments and connect them to form a point at each end. It should look something like this: Δ
to contruct a triangle you have to first draw a slanted triangle. then draw a slanted triangle for the right side. the draw a straight line at the bottom