How to find an equation of line parallel to a line?

Answers

Answer 1

Answer:
If two lines are parallel, then they have the same slope. Take the slope
of the line that you know, and use it for the new line. If you also need to
find the intercept of the new line, then you need some more information ...
the intercept is not the same as the line that you know.

Answer 2

Answer:

Final answer:

To find the equation of a line parallel to a given line, identify the slope of the given line and choose any point on that line, then use the point-slope formula to find the equation of the parallel line.

Explanation:

To find the equation of a line parallel to a given line, follow these steps:

Identify the slope of the given line. Let's call it 'm'.
Select any point on the given line. Let's call the coordinates of this point (x₁, y₁).
Use the point-slope formula, y - y₁ = m(x - x₁), where (x, y) represents any point on the parallel line.
Simplify the equation to get the final equation of the line parallel to the given line.

Let me know if you need further assistance!

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Related Questions

Cecilia says she can use addition to solve multiplication problems. is cecilia correct?
Evaluate the following y^2-5y+2
Help the image says it all
Two friends, Bob and Ben, each buy one lottery ticket. Each ticket contains six numbers from a total of one hundred numbers (0–99). Bob chooses the numbers 1, 2, 3, 4, 5, 6, and Ben chooses the numbers 39, 45, 66, 72, 74, 89. Who has a higher probability of winning?
Which number is lower?A) 4.8b) -9.9

Solve
8 - (2x - 9) = 17-24

Answers

Answer:

x=12

Step-by-step explanation:

8-(2x-+9)=17-24

8-2x=17-24-9

8-2x=-7+-9

8-2x=-16

-2x=-16-8

-2x=-24

x=-24/-2

x=12

8-(2x-9)=17-24
8 - 2x -+9 = -7
-2x+17=-7
-17 -17
-2x = -24
/-2. /-2

x = 12

A candy machine is filled with candy. The weight of the candy can differ from the desired 84 ounce weight by no more than 0.5 ounces. Solve the absolute value equation given in order to find the heaviest and lightest acceptable weights for the candy machine.|x – 84| = 0.5

Answers

$Formula\ for\ absolute\ value\n\n |a|=a,\ for\ a \geq 0\n or\n|a|=-a,\ for\ a<0\n\n|x-84|=0,5\n\n x-84=-0,5\ \ \ or\ \ \ \ x-84=0,5\n x=-0,5+84\ \ \ \ or \ \ \ x=0,5+84\n x=83,5\ \ \ \ \ \ \ \ \ \ \ or\ \ \ x=84,5\n\nThe\ lightes\weight\ is\ 83,5\ ounce\ and\ the\ heaviest\ is\ 84,5\ ounce.$

What two numbers multiply to 44 and add up to 12?

Answers

This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.    x*y = 44 ..........(a)

Add up to 12. x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0, a = 1, b = -12, c = 44

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a

x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number. Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2 or (12 - √-32 )/ 2

x = (12 + 4i√2 )/ 2 (12 - 4i√2 )/ 2

x = 12/2 + (4i√2)/2 12/2 - (4i√2)/2

x = 6 + 2i√2 or    6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2, y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2, y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2

x = 6 + 2i√2, y = 6 - 2i√2

x = 6 - 2i√2, y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2

$xy=44\n x+y=12\n\n xy=44\n x=12-y\n\n (12-y)y=44\n 12y-y^2=44\n y^2-12y+44=0\n y^2-12y+36+8=0\n (y-6)^2=-8$

No solutions in real numbers.

In complex numbers:
$(y-6)^2=-8\n y-6=-√(-8) \vee y-6=√(-8)\n y=6-2\sqrt2 i \vee y=6+2\sqrt2 i\n\n x=12-(6-2\sqrt2i) \vee x=12-(6+2\sqrt2i)\n x=12-6+2\sqrt2i \vee x=12-6-2\sqrt2i\n x=6+2\sqrt2i \vee x=6-2\sqrt2i$

These numbers are $6-2\sqrt2i$ and $6+2\sqrt2i$ .

3 A linear function is graphed below.7 (3,5)
X
(-1,-5)
What is the y-intercept of this graphed line?
PLEASE HELP!!!!!!

Answers

I believe the answer is b)-3.
The y-intercept is when a point passes through the y-axis. Hope this helps:)

Final answer:

To find the y-intercept of the given linear function, first, the slope of the function is calculated using the provided points. Then, the slope and one pair of coordinates are substituted into the y = mx + b equation to solve for 'b', which is the y-intercept.

Explanation:

In mathematics, specifically in the context of linear functions, the y-intercept is the point at which the line crosses the y-axis. From the provided points, however, it's not immediately clear what the y-intercept is.

To find the y-intercept, we need to determine the line's equation first. The equation of a line can be represented in the form y = mx + b, where 'm' is the slope of the line and 'b' is the y-intercept. To find the slope, we use the formula (y2 - y1) / (x2 - x1), substituting the given points. After calculating the slope, we can plug one pair of the given coordinates into the equation y = mx + b, and solve for 'b', which gives us the y-intercept.

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A swimming pool holds 900 cubic meters of water. If its length is 20 meters and its height is 3 meters, find its width

Answers

V=900m³

V=L*w*h

V=20*3*w
V=60*w

60*w=900

w=900/60
w=15m

$Volume \ of \ a \ Cuboid: \n \n V=9000 m^3 \nthe \ length : \ l=20 \ m \n the \ height: \ h=3 m \n the \ width : \ w= ? \n \nV= l\cdot w \cdot h \n \n900 =20 \cdot w \cdot 3 \n \n900=60w \ \ / :60\n \n w=15 \ m \n\nAnswer : \ A \ swimming \ holds \ 15 \ meters\ the \ width .$

y=-3x+5

5x - 4y= -3

solvining systems of equations by substitution

Answers

$\left\{\begin{array}{ccc}y=-3x+5\n5x-4y=-3\end{array}\right\n\n\nsubstitute\n\n5x-4(-3x+5)=-3\n5x+12x-20=-3\n17x-20=-3\n17x=-3+20\n17x=17\ \ \ \ /:17\nx=1\n\ny=-3\cdot1+5=-3+5=2\n\n \left\{\begin{array}{ccc}x=1\ny=2\end{array}\right$

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