DeShawn uses 3/4 of a box of rice to cook dinner. The portion he uses weighs 12 ounces. Write and solve and equation to find the weight of the full box kf rice.
Answers
Answer 1
Answer:
Answer:
Step-by-step explanation:
we know that
of a box of rice weighs
ounces
so by proportion
Find the weight of the full box of rice
Answer 2
Answer:
3/4 box = 12 oz
we first need to find 1/4 of a box. to do that divide both sides by 3
1/4 box = 4 oz
for a full box which is 4/4 multiply both sides by 4
1/4 x (4) = 4 x (4) oz
4/4 ( or one whole) = 16 oz
we first need to find 1/4 of a box. to do that divide both sides by 3
1/4 box = 4 oz
for a full box which is 4/4 multiply both sides by 4
1/4 x (4) = 4 x (4) oz
4/4 ( or one whole) = 16 oz
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Answers
Length is 95 yards.
The perimeter of a rectangle is the sum of four sides. The four sides are either its length or width.
A rectangle has four sides where its angles are all right angles and its opposite sides are congruent or of equal size.
Perimeter = 2length + 2width ==> P = 2L + 2W
354 = 2L + 2(82)
354 = 2L + 164
to get the length. we must transfer all like signs.
2L = 354 - 164
2L = 190
2L / 2 = 190 / 2
L = 95 yards.
The perimeter of a rectangle is the sum of four sides. The four sides are either its length or width.
A rectangle has four sides where its angles are all right angles and its opposite sides are congruent or of equal size.
Perimeter = 2length + 2width ==> P = 2L + 2W
354 = 2L + 2(82)
354 = 2L + 164
to get the length. we must transfer all like signs.
2L = 354 - 164
2L = 190
2L / 2 = 190 / 2
L = 95 yards.
The answer of the length is 95
Answers
x=12 and y=40. If you divide 20 by 50 you get 2.5 which is the scale factor. To find the values of x and y you need to either multiply or divide 2.5 from the given values.
Answers
Let's write an equation for what David charges.
Let x equal the number of hours he has been moving lawns and y be the charge.
Every hour, you must add another $5.50.
This is the same as multiplying the number of hours by 5.50.
We also need to add that $15 at the beginning. This leaves our equation as
Now, let's write one for Ari.
6.25 per hour...6.25x.
Add the 12 and we get
To find when the two are equal, we can set up this equation:
Now, let's simplify. Since all of our decimals are either halves or quarters, you can multiply everything by 4 to get rid of them.
Subtract 22x from each side to get x on one side.
Subtract 26 from each side to get x alone.
Divide by 26 to find the value of x.
What does this tell us? Well, it tells us that when our number of hours reaches 1.346, their charges are equal.
(The .346 can be estimated as around 20 minutes because it's pretty close to .333, or a third of an hour. This puts 1.346 hours at an hour and 20 minutes.)
We still haven't answered one part of the question, though...after that 1:20 time frame, who is charging more? Well, let's say we had them mow lawns for two hours. Using 2 for x in those earlier equations gives us these values:
%2B15%3D11%2B15%3D26)
%2B12%3D13%2B12%3D25)
It seems that Ari charges less than David past that 1:20 point.
Since the question asked "when is Ari's charge greater than or equal to David's" we would respond by saying whenever he mows lawns for less than an hour and 20 minutes.
Let x equal the number of hours he has been moving lawns and y be the charge.
Every hour, you must add another $5.50.
This is the same as multiplying the number of hours by 5.50.
We also need to add that $15 at the beginning. This leaves our equation as
Now, let's write one for Ari.
6.25 per hour...6.25x.
Add the 12 and we get
To find when the two are equal, we can set up this equation:
Now, let's simplify. Since all of our decimals are either halves or quarters, you can multiply everything by 4 to get rid of them.
Subtract 22x from each side to get x on one side.
Subtract 26 from each side to get x alone.
Divide by 26 to find the value of x.
What does this tell us? Well, it tells us that when our number of hours reaches 1.346, their charges are equal.
(The .346 can be estimated as around 20 minutes because it's pretty close to .333, or a third of an hour. This puts 1.346 hours at an hour and 20 minutes.)
We still haven't answered one part of the question, though...after that 1:20 time frame, who is charging more? Well, let's say we had them mow lawns for two hours. Using 2 for x in those earlier equations gives us these values:
It seems that Ari charges less than David past that 1:20 point.
Since the question asked "when is Ari's charge greater than or equal to David's" we would respond by saying whenever he mows lawns for less than an hour and 20 minutes.
Answers
Isn't this actually 3,791 (?)
The answer is 3,751, 9-8 is 1 and so on
Answers
You have said that he used 180 in the first two weeks.
That left him with 200 at the end of the first two weeks.
Then you said that he had 2 left after another 2 weeks.
So during those 2 weeks, he used (200 - 2) = 198 in the 2nd 2 weeks.
What we all expected has not happened at all: Frank is not slowing down !
But, even so, we have to ask ourselves just what Frank is doing with them all.
Nobody can blame you for wondering.
I think it might be 198 because it has after the 2nd week he has 200 left and if he has 2 on the 4th week he uses 198 tell me if it was useful
Answers
Luckily 22 is half of 44 so this is not too hard.
If 44 is 44% 100 and 22 is half of 44, we can just use this info and find half of 100 to give us our answer.
100/2=50
So 22 is 44% of 50
If 44 is 44% 100 and 22 is half of 44, we can just use this info and find half of 100 to give us our answer.
100/2=50
So 22 is 44% of 50
22 is half of 44 by 22 and 22 is 44% of 50
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