Hailey records the weights of five dogs of one breed and five dogs of another breed.What can she infer about the weights of Breed 1 dogs and Breed 2 dogs?

Breed 1: {45, 38, 49, 52, 51}

Breed 2: {36, 35, 44, 50, 40}

Breed 1 dogs and Breed 2 dogs have similar weight distributions.

Breed 1 dogs and Breed 2 dogs have no overlap in their weight distributions.

Breed 1 dogs and Breed 2 dogs have somewhat similar weight distributions.

Breed 1 dogs and Breed 2 dogs have identical weight distributions.

Answers

Answer 1

Answer:

She infer about the weights of Breed 1 dogs and Breed 2 dogs is;

Breed 1 dogs and Breed 2 dogs have no overlap in their weight distributions.

Hence, Option B is the correct answer.

What is set?

A set is a collection of well defined elements or objects. A set is denoted by a capital letter symbol, and the cardinal number of a set, enclosed in a curly bracket, denotes the number of elements in a finite set.

Given that;

Breed 1 (38, 45, 49, 51, 52)

Breed 2 (35, 36, 40, 44, 50)

Now, comparing them is simpler. You can tell right immediately that they don't quite match and that they do overlap. so C or D cannot be the case.

As they are over a comparable range, I would say B, although the spread is different for both.

To learn more about set theory visit:

brainly.com/question/18877365

#SPJ3

Answer 2

Answer: If it is single answer type question, the answer is

Breed 1 dogs and Breed 2 dogs have somewhat similar weight distributions.

Hope it helps!

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25g = 25,000
g=1000
im doing math homework and need help asap!

Answers

Ten Thousand.

Hope this helped. :) We worked together. :D

100,000 welcome.. and this is it

Which of the following is the solution to 9|x+4|>54 ?

Answers

Answer:

x < -10, x > 2

Step-by-step explanation:

9|x+4| > 54

|x+4| > 6

Split the absolute value into two equation, positive and negative.

1.)POSITIVE

x+4 > 6

x > 2

2.)NEGATIVE

-(x+4) > 6

-x - 4 > 6

-x > 10

x < -10

Answer:

$\large\boxed{x<-10\ \vee\ x>2\to x\in(-\infty,\ -10)\ \cup\ (2,\ \infty)}$

Step-by-step explanation:

$9|x+4|>54\qquad\text{divide both sides by 9}\n\n(9|x+4|)/(9)>(54)/(9)\n\n|x+4|>6\iff x+4>6\ \vee\ x+4<-6\n\nx+4>6\qquad\text{subtract 4 from both sides}\n\nx+4-4>6-4\n\nx>2\n\nx+4<-6\qquad\text{subtract 4 from both sides}\n\nx+4-4<-6-4\n\nx<-10$

1.work out 1/2 + 5/62.work out 3/4 x 2/7

Please help, I have never been able to work these out although there so simple .-.

Answers

1. First find the LCD of the two fractions.
They share the denominator 6.
Turn 1/2 into a fraction with a denominator of 6.
2*3=6, so 1*3=3
3/6
Now add.
Leave denominators alone, but add numerators.
3+5=8
8/6
Now simplify.
Divide both by 2.
8/2=4
6/2=3
4/3 is your answer or 1 1/3
2. Multiply straight across.
3*2=6
4*7=28
6/28
Simplify
You get 3/14 as your answer.

Maria is tossing a fair coin. She tosses the coin ten times and it lands on heads eight times. If Maria tosses the coin an eleventh time, what is the probability that it will land on heads?A) 1/5
B) 1/2
C) 4/5
D) 3/2

Answers

The correct answer is B.
The eleventh toss of a coin is independent from previous tosses. So regardless of what happened before, the chance to get heads is always 1/2.

What is negative 3/5 multiplied by (negative 7) or as written -3/5*(-7)=

Answers

Answer:

21/5 = 4 1/5

Step-by-step explanation:

minus multiplied by minus vanishes itself

7 i basically 7/1 so you multiplay 3 with 7 and 5 with 1 and you get 21/5

Answer:

$(21)/(5)$

Step-by-step explanation:

Note that ( -)( -) = +

Hence

- $(3)/(5)$ × - 7

= $(3(7))/(5)$ = $(21)/(5)$

Factor completely 3x2 - 21.

Answers

3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go. But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:

3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.

$3x^2-21=3(x^2-7)=3[x^2-(\sqrt7)^2]=3(x-\sqrt7)(x+\sqrt7)$

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