The sum of two consecutive odd numbers is 156 . What are the numbers
Answers
Answer 1
Answer:
You would first write out: x+x+2= 156. Once you've got that, you add the 2 x's together and get: 2x+2=156. Now that you have them together, subtract 2 on both sides and you get: 2x=154. Solve for x by dividing 2 on both sides and you get 77 as x. Now, you would know the 2 numbers, which would be 77 and 79.
I hope this helps. :-)
I hope this helps. :-)
Answer 2
Answer:
consecutive odd numbers are represented as
x=first odd
x+2=second odd
and so ono
so the 2 numbers are
x and x+2
so
x+x+2=156
subtract 2 from both sdies
2x=154
divide by 2
x=77
the first number=77
x+2=second number=79
the numbers are 77 and 79
x=first odd
x+2=second odd
and so ono
so the 2 numbers are
x and x+2
so
x+x+2=156
subtract 2 from both sdies
2x=154
divide by 2
x=77
the first number=77
x+2=second number=79
the numbers are 77 and 79
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Answer:
1 3/8
Step-by-step explanation:
First, change the mixed fraction to improper fraction.
2 3/4 = 8/4 + 3/4 = 11/4
1/2 of 11/4 = (11/4)(1/2) = 11/8
11/4 - 11/8 = 22/8 - 11/8 = 11/8
11/8, or 1 3/8 is your answer.
~
Answers
10,000 ten thousand
easy.
easy.
10,000 ten thousand i think
Answers
First you want to add a decimal after the first one to make it 1.41. Now you want to count the amount of places after the 1. It would be 8 places for 141000000 in scientific notation is 1.41 x 
.
To convert it to scientific notation, first you have to move the decimal to the right of the first number = 1.41. Second, you see how many places it takes to get back to the original number = 8 digits. Third, you multiply the new number by 10 to the 8th power = 1.41 × 10^{8} → scientific notation
Answers
30.70 is the nearest tenth that is rounded
it would be like I think about 31.70 I think
Answers
I assume you mean 3.25 repeating as in the .25 repeating, not just the 5 or something like that. Anyways, here's the solution:
Let x = 3.25 repeating
100x = 325.25 repeating on the 0.25 (you can do this by just moving the decimal place back 2 times, and since repeating decimals go on forever, it's like you just added another "2" and "5" to the front right behind the 3. But it is still mathematically correct. Anyways, we subtract 1x from both sides, but on the right side of the equation, we actually substitute the value of x in, so it would be
100x-x on the left, and
325.25 repeating - 3.25 repeating on the right side.
On the left, 100x becomes
99x
and on the right side, the repeating decimals cancel out to give you
322 (subtracting the 3 still)
so we currently have
99x=322
divide both sides by 99 to get
x = 322/99
which cannot be simplified, so the final fraction is
or
Let x = 3.25 repeating
100x = 325.25 repeating on the 0.25 (you can do this by just moving the decimal place back 2 times, and since repeating decimals go on forever, it's like you just added another "2" and "5" to the front right behind the 3. But it is still mathematically correct. Anyways, we subtract 1x from both sides, but on the right side of the equation, we actually substitute the value of x in, so it would be
100x-x on the left, and
325.25 repeating - 3.25 repeating on the right side.
On the left, 100x becomes
99x
and on the right side, the repeating decimals cancel out to give you
322 (subtracting the 3 still)
so we currently have
99x=322
divide both sides by 99 to get
x = 322/99
which cannot be simplified, so the final fraction is
or
Answers
178.
If number CLXXVIII is within to text or sentence it should be read in its equivalent in arabic numbers, in this case 178.
:)
If number CLXXVIII is within to text or sentence it should be read in its equivalent in arabic numbers, in this case 178.
:)
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