MATHEMATICS HIGH SCHOOL

Which measurement is not equivalent to the others?500 cm
5 m
0.5 km
5,000 mm

Answers

Answer 1
Answer: The answer is C. 500 cm = 5 m, and 5,000 mm.

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Many bicycles have 26 inch diameter wheels. The low gear attached to your pedals has a radius of 2.2 inches. The low rear gear, driven by the chain attached to the front gear, has a diameter of 3 inches. How far does the bike travel in one rotation of the pedals, i.e. the front gear revolves once.
What is the directrix of the parabola defined by 1/4(y 3)=(x-2)^2?
HELP ME PLZ ! Solve for x
PLZ HELP URGENT!!!!!!!!!f(x) = -3x2 + 2x - 7f(-1) = A) -12 B) -8 C) -6 D) 0
Which costs more per issue, an 18-issue subscription for $40.50 or a 12-issue subscription for $33.60? Explain. (Make sure to show your work and explain your solution Plz.)

Please help with number 24 !!

Answers

The answer is F. y=2.5x. This is because if you multiply each pound (x)  from the table by 2.5, you will get the cost (y). Hope this helps!
If y varies directly with respect to x, then
y = k*x
Solving for k, we get
k = y/x

Pick any column of (x,y) values and plug it into the equation
I'm going to pick (x,y) = (4,10)
k = y/x
k = 10/4
k = 5/2
k = 2.5

So the equation is y = 2.5*x or simply y = 2.5x
Answer is choice F

What is 807.3 divided by 9

Answers

Answer: 807.3/9= 89.7

Step-by-step explanation:

Arrange the equations in the correct sequence to find the inverse of f(x)=y=3x/8+x

Answers

To find the inverse of the the function, it must be arranged in such a way that the independent variable be on the left side and the dependent variable on the right. So,
f(x) = y = 3x/ (8 + x)
y (8 + x) = 3x
8y + xy = 3x
8y = 3x - xy
8y = x (3 - y)
8y / (3-y) = x
x = 8y / (3 -y)

Therefore,
f-(x) = f(y) = x = 8y/ (3 - y)

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?a. 37.68 sq. in.
b. 452.16 sq. in.
c. 18.84 sq. in.
d. 113.04 sq. in.

Answers

we know that

Area of the circle is equal to

A=\pi r^(2)

where

r is the radius

in this problem

diameter=12\ in \n radius=diameter/2\n radius=12/2\n radius=6\ in

A=3.14* 6^(2)

A=113.04 in^(2)

therefore

the answer is the option

d. 113.04 sq. in.

The area of the Frisbee is about 113 in.² ( Option D )

Further explanation

The basic formula that need to be recalled is:

Circular Area = π x R²

Circle Circumference = 2 x π x R

where:

R = radius of circle

The area of sector:

\text{Area of Sector} = \frac{\text{Central Angle}}{2 \pi} * \text{Area of Circle}

The length of arc:

\text{Length of Arc} = \frac{\text{Central Angle}}{2 \pi} * \text{Circumference of Circle}

Let us now tackle the problem!

Given:

Diameter of Frisbee = d = 12 in

Unknown:

Area of Frisbee = A = ?

Solution:

Area of the Frisbee could be calculated using the area of circle as follows:

A = (1)/(4) \pi d^2

A = (1)/(4) * \pi * 12^2

A = 36 \pi ~ in.^2

A \approx \boxed {113.10 ~ in.^2}

The closest option available will be option D. 113 in.²

Learn more

Answer details

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse, Circle , Arc , Sector , Area, Inches , Frisbee , Diameter , Radius , Trigonometry ,

Given that 6x = 7y, find the ratio x : y.

Answers

7:6

reverse the numbers when given a ratio similar to this one. 6x7=42 and 7x6=42 so x is 6 y is 7

Hope this helps.
the only thing i can think would work is 6*7=7*6

42=42

What is the value of the ratio of the surface area to the volume of the right prism? A.
1.4

B.
1.07

C.
0.94

D.
0.7

length is 6
height is 3
width is 5

Answers

so first fin the area then surface area and the volume
volume=legnth times width times heigh ttimes width=3 times 5 times 6=90
volume=90
surface area=(2 times 3 times 5)+(2 times 3 times 6)+(2 times 5 times 6)=(2 times 15)+(2 times 18)+(2 times 30)=30+36+60=126

volume=90
surface area=126
radio fo surface area to volume
90:126
simplify and treat as fraction
5:7
since they area all decimals they expect us to divide
5/7=.714
the closest answer is D, 0.7

the answer is D 0.7

The answer is A. 1.4
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