The dimensions are length equal to 9 inches and width equal to 6 inches.
It is given that length of rectangularframe is three less than twice the width and its perimeter is 30 inches.
We have to find out the dimensions of the frame.
What is the perimeter of a rectangle ?
The perimeter of a rectangle is 2 ( b + l ) , where b is width and l is the length of the rectangle.
As per the question ;
Length of rectangularframe is three less than twice the width.
Let's assume width be x.
So ;
Length will be ;
= 2x - 3
We know that ;
Perimeter of a rectangle is given by ;
P = 2 ( b + l )
⇒ 30 = 2 ( x + 2x - 3 )
⇒ 30 = 2 × ( 3x - 3 )
⇒ 30 = 6x - 6
⇒ 6x = 36
⇒ x = 6 inches
So ;
width will be 6 inches and length will be ;
l = 2x - 3
l = 2 × 6 - 3
l = 12 - 3
length = 9 inches
Thus , the dimensions are length equal to 9 inches and width equal to 6 inches.
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Answer: 340
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
t/15-t/35-(1/15)=0
4.1 Find the Least Common Multiple
The left denominator is : 15
The right denominator is : 35
Least Common Multiple:
105
4.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 7
Right_M = L.C.M / R_Deno = 3
4.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier.
4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
5.1 Find the Least Common Multiple
The left denominator is : 105
The right denominator is : 15
Least Common Multiple:
105
5.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 1
Right_M = L.C.M / R_Deno = 7
5.3 Rewrite the two fractions into equivalent fractions
5.4 Adding up the two equivalent fractions
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
Now, on the left hand side, the 105 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
4t-7 = 0
6.2 Solve : 4t-7 = 0
Add 7 to both sides of the equation :
4t = 7
Divide both sides of the equation by 4:
t = 7/4 = 1.750
give me the all steps of that equation
Answer:
x=0
Step-by-step explanation:
24+x=9x+4*6
First, simplify 4*6 into 24:
24+x=9x+24
No, subtract 24 on each side:
x=9x
This wouldn't be possible except with one number that could represent x:
0.
If we substitute in 0 for x, we get:
0=9*0
9*0 is 0:
0=0
Hey! That looks like a koamoji!! :P
But it means, 0 equals 0.
Which is correct.