A single-cell amoeba doubles every 3 days. how long would it take on amoeba to produce a population of about 10,000 amoebae?

Answers

Answer 1
Answer: 2^n=10,000
2^14=10,000
d=3n
d=3(14)
d=42

d=days
n=number of times of reproduction

Answer 2
Answer:

Final answer:

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Explanation:

To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.

Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Learn more about Exponential Growth

brainly.com/question/31903

#SPJ11


Related Questions

Which measurement is not equivalent to the others?2 quart 8 cups 72 fl. oz. 4 pints
What is 2,200 yards in miles? Round to the nearest tenth of a mile.
A pelican consumes 33 1/3% of its body weight in one meal. Write this percent as a fraction in simplest form.
The fence along the length of a ranch measures 4,450.5 meters and the fence along the width of a ranch measures 2,890 meters.The length of the fence is how many kilometers longer than the width? _______ km
Select the correct solution set. -7x ≥ 56 {x | x ≤ -8} {x | x ≥ -8} {x | x ≥ 8}

1. Use a compass to draw a large circle.2. Without changing the compass setting, place the point of the compass on the circle and make a mark that intersects the circle.

3. Move the point of the compass to the mark you made and make another mark that intersects the circle.

4. Continue in this way around the circle until you come back to the first mark.

(Hint: The last mark might not coincide precisely with the first mark, but your drawing should look something like the sketch.)

5. Select one of the marks on the circle and use a straightedge to draw line segments connecting that mark to all the marks that are not next to it.

6. Repeat the process for each mark on the circle.

With the design you created in the previous question. Select a pair of adjacent compass marks on the circle. Then follow these instructions and answer the question. 1. Make a crease by folding the paper so that the two marks coincide with each other. When you open the paper, the crease will show you the midpoint along the circle between the two marks. 2. Repeat the process to find the midpoint between each pair of marks on the circle. 3. Use a straightedge to draw line segments connecting each midpoint to the midpoint that is next to it. What type of figure did you create?

Answers

So, the first shape is a pentagon, and the second figure, the one asked for, is a decagon (ten sided polygon), because each 'midpoint line' had two ends, which were factored in and doubled the amount of sides.

Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, andm∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.

Answers

         m∠A + m∠B = 90
(3x + 5) + (2x - 15) = 90
(3x + 2x) + (5 - 15) = 90
                  5x - 10 = 90
                      + 10  + 10
                         5x = 100
                          5      5
                           x = 20

m∠A = 3x + 5
m∠A = 3(20) + 5
m∠A = 60 + 5
m∠A = 65

m∠B = 2x - 15
m∠B = 2(20) - 15
m∠B = 40 - 15
m∠B = 25
m∠A + m∠B = 90

(3x + 5) + (2x - 15) = 90

(3x + 2x) + (5 - 15) = 90

5x - 10 = 90

5x - 10 +10 = 90+10

5x = 100

5x/5 = 100/5      Divide \ both \ sides \ by \ 5

x = 20                 Solutions

m∠A = 3x + 5     (x=20)

m∠A = 3(20) + 5          Substitute \ x \ for \ 20

m∠A = 60 + 5               Simplify

m∠A = 65


m∠B = 2x - 15

m∠B = 2(20) - 15

m∠B = 40 - 15

m∠B = 25

Need the answer in under 5 minutes

Answers

The answer to the question is 206.25
6600 / 32 = 206.25

Try doing
32 * 100 = 3200
32 * 200 = 6400 (Your cllloossee)
32 * 205 = 6560
32 * 206 = 6592
Okay so any higher and you know your gonna be over so now u just gotta find the remainder which i'll just tell u, 25. lol

Two numbers are randomly selected from integers 1 through 9. What is the probability that only one of the integers is odd given that the sum of the two numbers is odd?1/4

1

40/81

5/40

Answers


Another one where there's a danger of overthinking it !

The sum of ANY two integers is odd only if one is even and one is odd.

If they're both odd OR both even, then their sum is even.

So if their sum is odd, then one is odd and the other is even.

The probability is ' 1 ' (100%) .

4. Andy puts $4,000 into an account that offers 3% interest compounded annually. If no additional deposits or withdrawals are made, how much interest will he earn at the end of 6 years?​

Answers

Answer:

A=$ 4,000(1+.03)∧6  will all equal $4776.209 if round $4,776.21.

Step-by-step explanation:

I use the formula A = P(1 + r)

∧t for annually.

if your looking for the interest rate then use formula interest formula I/Pt = r . I stands for Interest amount paid in a specific time period / p which stands for Principle amount (the money before interest)  times T which is Time period involved which will equal r the interest rate.

Twice a number decreased by eight is sixteen.

Answers

The number is 12

16 plus 8 = 24/ 2= 12
16 plus 8 = 24 / 2 = 12