Median is the average. I'm pretty sure interquartile is the biggest number out of the two.
Add the numbers for the first semester up, then divide by the amount of numbers. Do the same for semester two, then pick the correct answer in the multiple choices... For example in semester one you'd divide the added amount by 5.
If i'm wrong i'd like anyone to let me know what I messed up in! :)
Solve by substitution. Show each step of your work.
2x + y = 7
3x + 5y = 14
Answers
Alright...simple...showing all steps.. ;)
You have the equations...
2x+y=7 and 3x+5y=14
To be able to even solve for any of the variables...multiply the equations by...2...and..3...
2x+y=7----*3--> 6x+3y=21 and 3x+5y=14-----*2--->6x+10y=28
Thus,
6x+3y=21 - 6x+10y=28
=========
-7y=-7
y=1
Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....
2x+(1)=7
2x+1=7 -1 -1
2x=6
x=3
Thus, the point of intersection for these two equations is (3,1)
One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?
Answers
Answer first number = 57 second number = 41 x= 16 + y x + 2y = 139