Yes, because P(W & C) = P(W) + P(C).
No; because P(W & C) P(W) + P(C).
Yes; because P(W & C) = P(W) P(C).
No; because P(W & C)# P(W). P(C).
Answer: I just answered on USA Test prep
C.)
Yes; because P(W &C) = P(W) • P(C).
Step-by-step explanation:
A.Parallel
B.Perpendicular
C.Neither
The given lines are perpendicular to each other because there slope are negative reciprocals of each other.
What is the point slope form of a line ?
Point slope form is used to represent a straight line using its slope and a point on the line.
The line passes through two points which are (-2,1) and (4,9). The other line passes through points which are (-3,8) and (5,2).
We know that the equation of a linein point slope form is given by :
(y - y1) = m (x - x1)
For the first line : (x , y) = (-2 , 1) and (x1 , y1) = (4 , 9)
So ,
(1 - 9) = m (-2 - 4)
-8 = m × -6
m = 8/6
For the other line : (x , y) = (-3 , 8) and (x1 , y1) = (5 , 2)
So,
(8 - 2) = m (-3 - 5)
6 = m × -8
m = -6 / 8
We know that if two lines are perpendicular then , there slopes are negative reciprocals of each other. i.e.,
8/6 can be written as :
= -1/(8/6) = -6/8
The lines are perpendicular to each other.
Therefore , the first line and second line are perpendicular to each other because there slope are negative reciprocals of each other.
Learn more about point slope formof a line here :
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Answer:
Perpendicular
Step-by-step explanation:
khan academy
Answer:
1.7 seconds, and
3.3 seconds
Step-by-step explanation:
We simply need to plug in 8 into h and solve for t:
Since cosine is negative in the 3rd quadrant as well, we need to figure out the 3rd quadrant equivalent of 2.13 radians.
First, π - 2.13 radians = 1.01 radians.
Then, we add 1.01 to π radians, so we get 4.15 radians
Solving from the last part, we have:
also, t = 3.30 seconds
*Note: we put the calculator mode in radians when solving
So, t = 1.7 seconds & 3.30 seconds
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
x/a + y/b = 1
Where 'a' is the x-intercept of the line and ‘b’ is the y-intercept of the line.
The linear function whose x-intercept is 5 and y-intercept is 60. Then the equation is given as,
x/5 + y/60 = 1
Convert the equation into a slope-intercept form. Then we have
x/5 + y/60 = 1
12x + y = 60
y = 60 - 12x
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
More about the linear equation link is given below.
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