In a sale, normal prices are reduced by 20%The sale price was £220
Calculate the normal price of the saddle
Answers
Answer 1
Answer:
so sale price= normal price-dicount
sale price=100%-20%=80%
therfor
220=80%of origonal price
80%
percent means parts out of 100
80%=80/100=8/10
220=8/10of origonal price
multiply both sdies by 10
2200=8 of origoal price
divide by 8
2200/8=275
origonal price=275
sale price=100%-20%=80%
therfor
220=80%of origonal price
80%
percent means parts out of 100
80%=80/100=8/10
220=8/10of origonal price
multiply both sdies by 10
2200=8 of origoal price
divide by 8
2200/8=275
origonal price=275
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(a) r = the weight of Rajesh's package and m = the weight of Mohib's package:
r = 2m + 3
r + m = 15
(b) The easiest way to solve this equation would be to use substitution. The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:
%2Bm%3D15%5C3m%2B3%3D15%5C3m%3D12%5Cm%3D4)
Now that we have m, we can plug it into one of the equations to find r:
%2B3%5Cr%3D8%2B3%5Cr%3D11)
So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds. This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.
(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis). The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.
r = 2m + 3
r + m = 15
(b) The easiest way to solve this equation would be to use substitution. The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:
Now that we have m, we can plug it into one of the equations to find r:
So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds. This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.
(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis). The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.
what textbook and pg # is this? I wanna be able to practice
Answers
If there is a pattern here to follow then the person before is wrong. If there is no pattern then you are wrong with all of the answers there
8+11=40 This is because in this pattern you take the equations before answer and add it to the equation you have so for the first equation you have 5 for the second equation you actually add 2+5+5=12 so the last one equals 8+11+21=40
Hope This helps!
8+11=40 This is because in this pattern you take the equations before answer and add it to the equation you have so for the first equation you have 5 for the second equation you actually add 2+5+5=12 so the last one equals 8+11+21=40
Hope This helps!
Answers
12 - (-2) (-4)
-2 * -4 = ?
A negative times a negative equals a positive value.
-2*-4 = 8
12 - 8 = ?
12-8 = 4
Because 4+8 = 12
Final answer: 4
-2 * -4 = ?
A negative times a negative equals a positive value.
-2*-4 = 8
12 - 8 = ?
12-8 = 4
Because 4+8 = 12
Final answer: 4
12-(-2)(-4)
= 12-(2*4)
= 12- 8
= 4
The final answer is 4~
= 12-(2*4)
= 12- 8
= 4
The final answer is 4~
Answers
Answer:
That is so cool
Step-by-step explanation:
Wait was that the whole question
Answers
The square root of 25/9 is 5/3
square root of 25 = 5
square root of 9 = 3
therefore the square root of 25/9 = 5/3
square root of 9 = 3
therefore the square root of 25/9 = 5/3
Answers
Answer:
81
Step-by-step explanation:
(30)(34)
=1(34)
=(1)(81)
=81
the value of 3^0x3^4 without any exponents is 243
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