At the supermarket, rick finds that 6 pounds of raisins cost $12. what is the price per pound of raisins?

Answers

Answer 1

Answer: The price is $2 per pound

Answer 2

Answer: one pound of raisins would be $2
1 lb : ?
x6 x6
6lb : $12
x times 6 is 12, so it is 2
2 dollars a pound.

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Six blood pressure readings are 115, 120, 123, 121, 121, and 112 mm Hg. What is the average (mean) value?

Answers

Answer:

118.666666667 mmHg

Step-by-step explanation:

To find the average/mean of a set of values, you add all the values together, then divide them by the amount of values in the set.

115+120+123+121+121+112 = 712

Since there is 6 values, you divide this by 6.

712÷6 = 118.666666667 mmHg

Hope this helps!

Triangle ABC is similar to triangle QRS by the AA Similarity Postulate.Also, m∠A = 45° and m∠S = 75°.

What is m∠B?

_________ °

Answers

Answer:

Measure of ∠B is 60°

Step-by-step explanation:

Given triangle ABC is similar to triangle QRS.

m∠A = 45° and m∠S = 75°

we have to find the measure of ∠B.

As triangles are similar then corresponding angles are congruent.

⇒ ∠A≅∠Q, ∠B≅∠R, ∠C≅∠S

hence, m∠C=m∠S=75°

By angle sum property

m∠A+m∠B+m∠C=180°

⇒ 45°+m∠B+75°=180°

⇒ m∠B+120°=180°

⇒ m∠B=60°

hence, measure of ∠B is 60°

Angle B is 60 degrees

What is a simple formula to solve a math sequence? Or a couple formulas if possible? Thanks!

Answers

2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2

the nth term is denoted by $a_(n)$
the first term is represented by $a_(1)$

for arythmetic sequences, the nth tem is
$a_(n)=a_(1)(n-1)d$ where d=distance between each term

for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms

Round 6609707 rounded to the nearest ten thousand

Answers

That would be 6,610,000 answer

An amusement park has 11 roller coasters. In how many ways can you choose 4 of the roller coasters to ride during your visit to the park?

Answers

4!=4*3*2*1=24
11!=11*10*9*8*7*6*5*4*3*2*1=39916800
7!=7*6*5*4*3*2*1=5040
n choose k
how many ways are there to choose k rollercoasters from n choices?

$\left(\begin{array}{ccc}n\nk\end{array}\right)$ = $(n!)/(k!(n-k)!)$

$\left(\begin{array}{ccc}11\n4\end{array}\right)$ = $(11!)/(4!(11-4)!)$ = $(39916800)/(24(7)!)$ = $(39916800)/(24(5040))$ = $(39916800)/(120960)$ =330

330 ways

M = 1, (- 4, -6) does anyone know the answer to this

Answers

Hello,
Very clear your question !!!
I suppose m is the slope of a line
and the line passe through (-4,-6)

and you ask the equation of the line!

y+6=1(x+4)==>y=x-2

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