24. Congratulations! You have just won a jet ski worth $8000. The depreciated value of the jet ski (V) after t years is given by V = 8000 − 725t , 0 ≤ t ≤ 11.a. Use a graphing utility to graph the equation. Include a t-chart with at least 5 key points with your accurate labeled graph.
b. After how many years will the jet ski be worth $5100? Show all of your work or explain how you came up with your answer.
c. What will be the value of the jet ski after 9 years? Show all of your work or explain how you came up with your answer.
Answers
Answer 1
Answer:
So:
*V (in dollars) stands for the depreciated or non depreciated value of the jet ski.
*t (in years) stands for the amount of time that has passed. t is greater or equal to 0 and less than or equal to 11.
-------------------
Question (a):
Now V is a function of t. V=f(t).
When t=0, V=0 --> Point:(0,0)
When t=2, V=6550 --> Point (2, 6550)
When t=4, V=5100 --> Point (4, 5100)
When t=6, V=3650 --> Point (6, 3650)
When t=8, V=2200 --> Point (8,2200)
When t=11, V=25 --> Point: (11, 25)
So as the graph V=8000-725t is LINEAR, we can draw a line through the points mentioned above.
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Question (b): After how many years will the jet ski be worth $5100?
Answer: 4 years.
-----------------------
Question (c): What will be the value of the jet ski after 9 years?
%20%5C%5C%20%5C%5C%20%3D1475)
The answer is $1,475.00
*V (in dollars) stands for the depreciated or non depreciated value of the jet ski.
*t (in years) stands for the amount of time that has passed. t is greater or equal to 0 and less than or equal to 11.
-------------------
Question (a):
Now V is a function of t. V=f(t).
When t=0, V=0 --> Point:(0,0)
When t=2, V=6550 --> Point (2, 6550)
When t=4, V=5100 --> Point (4, 5100)
When t=6, V=3650 --> Point (6, 3650)
When t=8, V=2200 --> Point (8,2200)
When t=11, V=25 --> Point: (11, 25)
So as the graph V=8000-725t is LINEAR, we can draw a line through the points mentioned above.
------------------------
Question (b): After how many years will the jet ski be worth $5100?
Answer: 4 years.
-----------------------
Question (c): What will be the value of the jet ski after 9 years?
The answer is $1,475.00
Answer 2
Answer:
a) 
-intercept%3D8000)
b)
The value will be 5100 after 4 years.
c))
The value of the jet will be 1475 after 9 years.
Hope I helped bro, now i can sleep
b)
The value will be 5100 after 4 years.
c)
The value of the jet will be 1475 after 9 years.
Hope I helped bro, now i can sleep
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Answers
Let the length of equilateral triangle be x.
Each of the angle in an equilateral triangle is = 60°
The opposite to the 60° is the 18 inches. Hypotenuse is the side.
Sin 60° = 18 / Hypotenuse
Hypotenuse = 18 / Sin60°. Sin60° = √3 / 2
x = 18 / (√3 / 2)
= 18 / √3 * 2/1 = 36 / √3
x = 36 / √3
Rationalize the surd = 36 / √3 * (√3 / √3 ) = 36√3 / 3
x = 12√3 ≈ 12 * 1.732 ≈ 20.784
Length of side, x = 12√3 ≈ 20.784 inches.
Each of the angle in an equilateral triangle is = 60°
The opposite to the 60° is the 18 inches. Hypotenuse is the side.
Sin 60° = 18 / Hypotenuse
Hypotenuse = 18 / Sin60°. Sin60° = √3 / 2
x = 18 / (√3 / 2)
= 18 / √3 * 2/1 = 36 / √3
x = 36 / √3
Rationalize the surd = 36 / √3 * (√3 / √3 ) = 36√3 / 3
x = 12√3 ≈ 12 * 1.732 ≈ 20.784
Length of side, x = 12√3 ≈ 20.784 inches.
Answers
The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30 .
9 is not a factor of 30 .
30/3=10
30/2=15
30/5=6
30/6=5
30/9=3.333333333333
30/2=15
30/5=6
30/6=5
30/9=3.333333333333
Answers
oi,
Remember that V = Bh, so V = 120 * 5 = 600 ft³
I hope this helps!
Remember that V = Bh, so V = 120 * 5 = 600 ft³
I hope this helps!
Answers
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
11.333 m = radius
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h² ).
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m²
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
11.333 m = radius
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h² ).
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m²
Answers
We know that 8 x 3= 24
7/8=?/24
7 x 3=21
So the answer is 3
3/24
7/8=?/24
7 x 3=21
So the answer is 3
3/24
y= x^2-2x-1
vertex (?,?)