What is the area of this triangle?
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lets say the base is from x1,y2 to x1,y1 the distance is 6 units
1/2 times 6 times height
from x1,y1 to x3,y3 is 7 units to the right
1/2 times 6 times 7=3 itmes 7=21
area=21 square units or
21 units^2
The area of this triangle with three vertices (x₁, y₁) , (x₂, y₂) and (x₃, y₃) is,
A = 1/2 [[(x₁ (y₂ - y₃) + x₂ (y₃ - y₁) + x₃ (y₁ - y₂))]
We have to give that,
The three vertices of the triangle are,
(x₁, y₁) , (x₂, y₂) and (x₃, y₃)
Since a triangle is a three-sided polygon, which has three vertices and three angles it has the sum of 180 degrees.
Hence,
The area of this triangle with three vertices (x₁, y₁) , (x₂, y₂) and (x₃, y₃) is,
A = 1/2 [[(x₁ (y₂ - y₃) + x₂ (y₃ - y₁) + x₃ (y₁ - y₂))]
So, the Formula is,
A = 1/2 [[(x₁ (y₂ - y₃) + x₂ (y₃ - y₁) + x₃ (y₁ - y₂))]
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B. 20 pounds
C. 24 pounds
D. 22 pounds
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Hope it helped
ThankYou
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Perimeter of the figure PQR is 91.42 cm.
What is Perimeter?
Perimeter of a straight sided figures or objects is the total length of it's boundary
Given figure PQR consists of an equilateral triangle and a semicircle.
Length of side of an equilateral triangle = 20 cm
Perimeter of equilateral triangle = sum of the length of three sides
Perimeter = 3 × 20 = 60 cm
Now circumference of a circle = 2πr, where r is the radius.
Here there is a semicircle, which is the half of the circle.
Circumference of semicircle = 2πr / 2 = πr
Here Diameter = 20 cm
Radius = 20 / 2 = 10 cm
Perimeter of semicircle = 10π = 31.42 cm
Total perimeter = 60 cm + 31.42 cm = 91.42 cm
Hence the total perimeter is 91.42 cm.
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Answer:
Option b
Step-by-step explanation:
As per central limit theorem, we know that if we draw a number of samples randomly from the population the sample mean for all the mean of samples will follow a normal distribution provided large samples are drawn.
The distribution which the sample mean follows is called the sampling distribution.
The distribution of various sample sizes will not follow any distribution. Hence I option wrong.
Distribution of values in the population are parameters and they do not follow any distribution. Option d , the values of the items selected will not follow any distribution
Only correct option is
(b) the distribution of the different possible values of the sample mean together with their respective probabilities of occurrence