How many small cubes are needed to completely fill the rectangular prism?

Answers

Answer 1
Answer: Do you have the volume of the rectangular prism? Or maybe just the side lengths?

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How do I solve 2x+3y=7, x-y=1

Answers

2x+3y=7
x-y=1

2x+3y=7
x=1+y

2*(1+y)+3y=7
x=1+y

2+2y+3y=7
x=1+y

5y=5       |(:5)
x=1+y

y=1
x=2

CHECK:
2x+3y=7
x-y=1

2*2 + 3*1 = 7     

x-y = 1
2-1 = 1

2x+3y=7                                               
2(2)+3y=7                                                                                              
4+3y=7
subtract 4 from both sides                  
3y=3                                             
divide both side by 3                          
y=1
 
2x+3y=7
2x+3=7
2x+3y=7
subtract 3y from both sides
2x=7-3y
divide both side by 2
x=3.5-1.5
x=2                                     

then you do the x-y=1

x-y=1
2-1=1
1=1

in the end both answers are 1 so that means that i did it right. that means that x=2 and y=1

QUESTION 4 Arrange these numbers from least to greatest:

Answers

i would help you with the numbers but i cant see the pic

−1 1/2−(+3 1/2)−(−5/8)

Answers

Answer:

-35/8

Step-by-step explanation:

−1 1/2−(3 1/2)−(−5/8)

Convert all fractions into improper fractions:

- 3/2 - (7/2) - (-5/8)

Make all denominators:

(-3*4)/(2*4)

-12/8 - ((7*4)/(2*4)) - (-5/8)

-12/8 - ((28)/(8)) + 5/8

-35/8

a marching band requires a tuba player to begin at the 50 yard line of a football field perpendicular to the 40 yard line. He then makes a 30 degree turn and marches at a diagonal back to the 50 yard line.Once he reaches the 50 yard line he must march forward until; he reaches his original starting position.If the tuba player travels 18 invhes with each marching pace how many paces must he take to complete the routine?

Answers

20/3 paces must he take to complete the routine.

How to find the steps he must take to complete the routine?

The marching band begins at the 50-yard line of a football field and marches perpendicular to the 40-yard line.

Hence,

So when the tuba players travel 18 inches with each marching pace, the paces are:

50+30+40 / 18 = 20 / 3

So, the answer is 20 / 3  paces.

Here, Distance divided by speed equals steps.

Learn more about problem-solving here: brainly.com/question/13818690

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well yes, i took 50, 40, 18 and added two 50. I then got 238 as the answer but honestly math is like my worse subject. I tried looking like examples on how to do it and in one of my math books but this what i got. I really hope i helped tho :)

Camillo estimates the weight of his dog. The veterinarian says that the dog weighs 84 pounds. The percent error in Camillo's estimates is less than 10%.Decide whether each of the following weight estimates could have been Camillo's estimate.
a. 80 pounds yes or no
b. 78 pounds yes or no
c. 94 pounds yes or no
d. 77 pounds yes or no
e. 92 pounds yes or no
f. 75 pounds yes or no

Answers

Answer:

A.Yes B.Yes C.No D.Yes E.No F.No

Step-by-step explanation:

10% of 84 is 8.4 and 84-8.4=76.6 and anything between 76.6-84 could have been the estimate.

Final answer:

Camillo's weight estimate could have been 80 pounds, 78 pounds, 77 pounds, or 92 pounds.

Explanation:

The percent error measures the discrepancy between an estimated value and an actual value. It is calculated using the formula: Percent Error = (|Measured Value - Actual Value| / Actual Value) * 100%. Since the given problem states that Camillo's estimate has a percent error less than 10%, we can calculate the percent error for each weight estimate and determine if it is less than 10%.

  • a. 80 pounds: Percent Error = (|80 - 84| / 84) * 100% = 4.76%, which is less than 10%. So, yes, this could have been Camillo's estimate.
  • b. 78 pounds: Percent Error = (|78 - 84| / 84) * 100% = 7.14%, which is less than 10%. So, yes, this could have been Camillo's estimate.
  • c. 94 pounds: Percent Error = (|94 - 84| / 84) * 100% = 11.9%, which is not less than 10%. So, no, this could not have been Camillo's estimate.
  • d. 77 pounds: Percent Error = (|77 - 84| / 84) * 100% = 8.33%, which is less than 10%. So, yes, this could have been Camillo's estimate.
  • e. 92 pounds: Percent Error = (|92 - 84| / 84) * 100% = 9.52%, which is less than 10%. So, yes, this could have been Camillo's estimate.
  • f. 75 pounds: Percent Error = (|75 - 84| / 84) * 100% = 10.71%, which is not less than 10%. So, no, this could not have been Camillo's estimate.

Learn more about Percent Error here:

brainly.com/question/20458240

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What is (x-2) * (x+2)

Answers

(x-2)*(x+2)

Distribute

(x)(x)+(x)(2)+(-2)(x)+(-2)(2)

x²+2x-2x-4

= x²-4


I hope that's help;0