List the next four multiples of the next fraction 2/6
$list the next four multiples of the next fraction 2/6 - 1$

Answers

Answer 1

Answer:

The four multiples of 2/6 are 4/12, 6/18, 8/24 and 10/30

What is fraction?

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator.

What is a multiple?

A multiple of a whole number is the product of the number and any countingnumber.

e.g. 3, 6 , 9 , 12 , 15 , 18 and so on are the multiples of 3.

given number: 2/6

now, we have to find the multiples for the fraction 2/6.

So,

2/6* 2/2

= 4/12

2/6* 3/3

=6/18

2/6*4/4

=8/24

2/6* 5/5

=10/30

All the four multiples can again reducible to fraction 2/6.

Hence, the four multiples are : 4/12, 6/18, 8/24 and 10/30

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Answer 2

Answer: 2/6 4/12 6/18 8/24 10/30 12/36 14/42 16/48

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What is the volume of a hemisphere with a radius of 3 cm, rounded to the nearest tenth of a cubic centimeter?

Answers

The Volume of sphere whose radius is 3 cm = 113 $cm^(3)$ (rounded to the nearest tenth)

Volume= 113 $cm^(3)$

What is Volume of sphere?

The volume of a sphere = 4/3 r³, where r is the radius of the sphere.

Volume of sphere = $(4)/(3) * \pi* r^(3)$

= $(4)/(3) * 3.14* (3)^(3)$

= 4 x 3.14 x 9

=113.04 $cm^(3)$

≈ 113 $cm^(3)$ (rounded to the nearest tenth)

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Final answer:

The volume of a hemisphere with a radius of 3 cm is approximately 56.6 cm³ when rounded to the nearest tenth of a cubic centimeter. This is calculated by halving the volume of a sphere with the same radius.

Explanation:

Calculating the Volume of a Hemisphere

The question asks for the volume of a hemisphere with a radius of 3 cm. The formula for the volume of a sphere is V = (4/3)πr³, and since a hemisphere is half of a sphere, the formula adapts to V = (1/2)(4/3)πr³. Using a radius (r) of 3 cm, we get V = (1/2)(4/3)π(3 cm)³.

Let's calculate the volume step by step:

First, calculate the volume of the full sphere using the radius of 3 cm: V = (4/3)π(3³) cm³
Compute the result: V = (4/3)(π)(27) cm³ = (36π) cm³
Since we want the volume of the hemisphere, we divide this number by 2: V = (36π/2) cm³ = (18π) cm³
Finally, we approximate π to 3.142 and round to the nearest tenth: V ≈ 18(3.142) cm³ ≈ 56.6 cm³

Therefore, the approximate volume of the hemisphere is 56.6 cm³, when rounded to the nearest tenth of a cubic centimeter.

Find the arithmetic combination of f(x) =x+2, g(x)=x-2

Answers

Answer:

The arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

Solution:

Given, two functions are f(x) = x + 2 and g(x) = x – 2

We need to find the arithmetic combinations of given two functions.

Arithmetic functions of f(x) and g(x) are (f + g)(x), (f – g)(x), (f $*$ g)(x), $\left((f)/(g)\right)(\mathrm{x})$

Now, (f + g)(x) = f(x) + g(x)

= x + 2 +x – 2

= 2x

Therefore (f + g)(x) = 2x

similarly,

(f - g)(x) = f(x) - g(x)

= x + 2 –(x – 2)

= x + 2 –x + 2

= 4

Therefore (f - g)(x) = 4

similarly,

(f $*$ g)(x) = f(x) $*$ g(x)

= (x + 2) $*$ (x – 2)

= x $*$ (x – 2) + 2 $*$ (x -2)

$=x^(2)-2 x+2 x-4$

$=x^(2)-4$

Therefore (f $*$ g)(x) = $x^(2)-4$

now,

$\left((f)/(g)\right)(\mathrm{x})=(f(x))/(g(x))$

$=(x+2)/(x-2)$

$((f)/(g))(x)$ = $(x+2)/(x-2)$

Hence arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

sally bought five dozen eggs from the grocery store to bake some cakes. She plans to bake the cakes. She plans to bake the cakes over eight days. How many eggs did Sally buy.

Answers

5 dozen eggs, or 60 (12×5)

5 dozen eggs is the answer

If 28% of a sum is 100.80 what is the sum

Answers

$360.00*.28= 100.80

Or do a portion

28%/100%=100.8/x

Then cross multiply

10080=28x

x=360

What is through :(0,5) and (-5,2)

Answers

Answer:

y = 3/5x + 5

Step-by-step explanation:

Gradient of the line

$(y_(2)-y_(1))/(x_(2)-x_(1)) \n\n(2 - 5)/(-5 - 0)\n\n(-3)/(-5)$

$(3)/(5)$

y = 3/5x + c

Substitute either point in to find c

y = 3/5x + c at (0,5)

5 = 3/5(0) + c

5 = 0 + c

5 = c

y = 3/5x + c at (-5,2)

2 = 3/5(-5) + c

2 = -3 + c

2 + 3 = c

5 = c

y = 3/5x + c

Replace c with 5

y = 3/5x + 5

4^2 + 5 • 3^2 – 4^2 ÷ 2^3

Answers

Following the order of operations:
4^2 + 5 * 3^2 – 4^2 / 2^3
16 + 5 * 3^2 – 4^2 / 2^3
16 + 5 * 9 – 4^2 / 2^3
16 + 5 * 9 – 16 / 2^3
16 + 5 * 9 – 16 / 8
16 + 45 – 16 / 8
16 + 45 – 2
61 – 2
59

The answer is 59

Remember BEDMAS
Brackets, Exponents, Division or Multiplication ( left to right), Addition or subtraction ( left to right)
And the dot between 5 and 3^2 means multiply.
4^2 + 5 · 3^2 - 4^2 ÷ 2^ 3

4×4 + 5 · 3×3 - 4×4 ÷ 2×2×2
16 + 5 · 9 - 16 ÷ 4×2
16 + 45 - 16 ÷ 8
16 + 45 - 2
61 - 2
59

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