If an average 7th grade student weighs 91 pounds and Hugo the Elephant weighs 18,130 pounds, about how many average 7th grade students would be needed to equal the weight of Hugo?

Answers

Answer 1
Answer: Divide 18,130 by 91 and you get 199.23 so it is 199 students. 
Answer 2
Answer: The elephant weighs 18,130, and we want to see how many seventh graders weighing 91 pounds it will take to equal the weight of the elephant.

To find our answer, we divide 18,130 by 91.

18,130÷91 = 199.2307

Since you said about how many average 7th grade students, it means you only need an estimate, not an exact number.

The final answer is 199 average seventh-grade students.

Have a wonderful day! :D


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A bank paid 2.3% interest on a money market account. What is 2.3% written as a decimal

Answers

1\%\ \ \rightarrow\ \ (1)/(100)=0.01 \n\n2.3\%\ \ \rightarrow\ \ x\n\nx= (2.3\%\cdot0.01)/(1\%) \ \ \ \Rightarrow\ \ \ x=0.023
2.3% is the same thing as 0.023 .

Subtract and simplify 10 - 5 1/8

Answers

10 - 5 1/8

Convert 5 1/8 into an improper fraction.

We do this by multiplying the denominator to the whole number and adding it to the numerator, and wee keep the denominator.

8 * 5 = 40 + 1 = 41/8

10 - 41/8

Convert 10 to a denominator of 8:

10 * 8 = 80
1 * 8 = 8

80/8 = 41/8

Subtract the numerators together and keep the denominator:

39/8

Convert to a mixed number:

4 7/8
10 = 80/8

5 1/8 = ((5x8)+1)/8 = 41/8

(80-41)/8 = 39/8

39/8 = 4 7/8

= 4 7/8

a store owner is arranging clothing on racks. She has 30 sweaters, 45 shirts and 15 pairs of jeans. She wants to put the same number of items on each rack, with only one type of item on each. How many items can she put on a rack?

Answers

I think what the teacher wants is 15  which is the greatest common factor of all three numbers and the factors of 15 are 
1 x 15 and 3 x 5 so the she can put one of each, or she can put 3 of each,
 or she can put 5 of each , or she can put 15 of each.

The problem is unclear however because as worded she could put 2 sweaters, 2 shirts and 2 pair of jeans.  I think the teacher wants all the jeans used.  The number 1,3,5 and 15 will use up all of the jeans.
1 jean on 15 racks
or 3 jeans on 5 racks
or 5 jeans on 3 racks
or 15 jeans on one rack


These are the sort of ambiguous word problems 4th graders are exposed to on a daily basis.  As the gentleman mentioned, the teacher expects 15, the largest common factor but 1 on each rack fits as well. It should have read “what’s the maximum number of the same item can he/she place on the racks?”

Help please if you can then thank you so much if you can't see number 4 and 5 then here.

Answers

Answer:

2) A- 8h 15m

3) C- 6h 59m

4) A- 37m

5) B- 1h 2m


Answer:

2.  8 hours and 15 mins

3. 7 hours 1 min

4. 37 mins

5. 1 hour 2 mins


How 7/3 compares to 2 1/3

Answers

7/3 written as a mixed fraction is 2 1/3

So 

7/3 = 2 1/3

Line segment AB has endpoints A(2, 9) and B(5, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has endpoints A′(43, 6) and B′(103, 163) . What is the scale factor of this dilation? 32
23
2
3

Answers

Answer:  The correct option is (B) (2)/(3).

Step-by-step explanation:  Given that the co-ordinates of the end-points of a line segment AB are A(2, 9) and B(5, 8). After being dilated about the origin (0, 0), the co-ordinates of the end-points of image A'B' are A^\prime\left((4)/(3),6\right) and B^\prime\left((10)/(3),(16)/(3)\right).

We are to find the scale factor of the dilation.

The scale factor of the dilation will be

S=\frac{\textup{length of the image line}}{\textup{length of the original line}}.

The lengths of the lines AB and A'B' are calculated using distance formula as follows:

AB=√((5-2)^2+(8-9)^2)=√(9+1)=√(10),\n\n\nA'B'=\sqrt{\left((10)/(3)-(4)/(3)\right)^2+\left((16)/(3)-6\right)^2\right)}=\sqrt{4+(4)/(9)}=\sqrt{(40)/(9)}=(2)/(3)√(10)~\textup{units}.

Therefore, the required scale factor of dilation is

S=(A'B')/(AB)=((2)/(3)√(10))/(√(10))=(2)/(3).

Thus, the scale factor of the dilation is (2)/(3).

Option (B) is CORRECT.

the answer is 2/3 
i took the test
hope this helps!