Monticello residents were surveyed concerning their preferences for candidates Moore and Allen in anupcoming election. Of the 800 respondents, 300 support neither Moore nor Allen, 100 support both Moore and
Allen, and 250 support only Moore. How many residents support Moore or Allen?

Answers

Answer 1
Answer: you just subtract 300 from 800 to get 500 people

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Help :,)(both questions)
F(x)=5x2−3x−1 and g(x)=2x2−x+3f(x)+g(x)= Question 18 options: 3x2−4x−4 3x2−2x−4 7x2+4x+3 7x2−4x+2

Solve equestion fast i give a lot point​

Answers

Answer:

X × $75000 = $75000

Step-by-step explanation:

Brainliest would be appreciated

2.) What amount presently must be invested earning 5.25% compounded continuouslyso that it will grow up to be worth $25,000 12 years from now?

Answers

The amount A resulting from a principal amount P being invested at rate r compounded continuously for time t is given by

... A = P·e^(rt)


FIll in your given values and solve for P.

... 25000 = P·e^(0.0525·12) = P·e^0.63

... P = 25000/e^0.63 ≈ 13314.80 . . . . . divide by the coefficient of P


The amount that must be invested is $13,314.80.

An initial investment (P) compounded continuously with a rate of interest (r) in time (t) will grow to amount (Q) is given by:

Q = P * e^(rt)

Q=25000, r=0.0525, t=12

25000 = P * e^(0.0525*12)

1.8776P = 25000

P = 13314.8

Suppose a stock is selling on a stock exchange for 6 3/4 dollars per share. If the price increases 3/4 per share, what is the new price of the stock? Leave your answer as a proper fraction or mixed number.

Answers

The new price of the stock which increases 3/4 per share is $ 7 1/2.

Given data:

A stock is selling on a stock exchange for 6 3/4 dollars per share.

If the price of the stock increases by 3/4 dollars per share, you can add 3/4 to the current price of 6 3/4 dollars per share:

6 3/4 + 3/4

To add the whole numbers and fractions separately:

6 + 0 + 3/4 + 3/4

Adding the whole numbers and fractions:

6 + 1 1/2

A = 7 1/2

Hence, the price of the new stock is $ 7 1/2

To learn more about fractions, refer:

brainly.com/question/29766013

#SPJ3

Step-by-step explanation:

If the price increases 3/4 per share, the new price of the stock =

6¾ + ¾ =

27 /4 + ¾ =

30 /4 =

15/2or7½

Find the next three numbers 1, 0.6, 0.36, 0.216

Answers

Answer: The answer is everytime you mutiply in by 0.6

Step-by-step explanation:

An ice cube tray holds 12 ice cubes. Each cube is 5 cm. what is the volume of all 12 cubes?

Answers

Cube is length of one side cubed (or to the third power)
This one side is 5 cm which means it's volume is 125cm^3 or cubic centimeters.
Multiply 125 * 12 to get the volume of all 12 cubes combined. 
(1500 cubic centimeters)
Hello!

To find the volume of one ice cube, you'll need to find the length, width, and height. In the question, it states that each cube is 5cm. So, 5cm will be the length, width, and height. So you'll need to multiply 5 three times (5*5*5) ---> (25*5) ---> (125).

The volume, V, of one ice cube is 125cm³

Now to find the total volume of all of the cubes, you'll need to multiply 125 by 12. After doing so, you'll get a volume of...

V=1500cm³

I hope this helps!

A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 7 students' scores on the exam after completing the course: 37,12,12,17,13,32,23 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to one decimal place.

Answers

Answer:

The 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).

Step-by-step explanation:

The net change in 7 students' scores on the exam after completing the course are:

S = {37 ,12 ,12 ,17 ,13 ,32 ,23}

Compute the sample mean and sample standard deviation as follows:

\bar x=(1)/(n)\sum x=(1)/(7)* 146=20.857\n\ns=\sqrt{(1)/(n-1)\sum (x-\bar x)^(2)}}=\sqrt{(1)/(7)* 622.8571}=10.189

As the population standard deviation is not known, a t-interval will be formed.

Compute the critical value of t for 80% confidence interval and 6 degrees of freedom as follows:

t_(\alpha/2, (n-1))=t_(0.20/2, (7-1))=t_(0.10,6)=1.415

*Use a t-table.

Compute the 80% confidence interval for the average net change in a student's score after completing the course as follows:

CI=\bar x\pm t_(\alpha/2, (n-1))*(s)/(√(n))

     =20.857\pm 1.415*(10.189)/(√(7))\n\n =20.857\pm 5.4493\n\n=(15.4077, 26.3063)\n\n\approx (15.4,26.3)

Thus, the 80% confidence interval for the average net change in a student's score after completing the course is (15.4, 26.3).