оооо
Answer:
15
Step-by-step explanation:
f(-5)= 5(-5)+40 = -25+40 = 15
You substitute -5 in place of x
vf = at – vi
a =
vi = vf – at
v =
vf = at + vi
a =
Equations can be used to solve for acceleration
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
• An equation of uniformly accelerated motion
V = vo + at or vf = vi + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
Acceleration is a change in speed within a certain time interval
a = Δv / Δ t
The velocity graph with respect to time (v-t) in this motion will be in the form of sloping straight lines with a gradient of tan θ = a
For acceleration that is positive (a> 0) is called accelerated motion, the graph is sloping upward, while for acceleration that is negative (a <0) is called slowed down motion, the graph is sloping downward
We complete the available answer choices
t = delta v over a.
vf = at - vi
a = d over t.
vi = vf - at
v = a over t.
vf = at + vi
a = delta v over t.
From the general equation of uniformly accelerated motion above, what is appropriate is:
1. t = delta v over a ---> can be used, a = v / t
2. vf = at - vi ---> cannot be used, it should be vf = vi + at
3. a = d over t .---> d = displacement has the formula: d = v x t, so this 3rd equation cannot be used
4. vi = vf - at ----> can be used
5. v = a over t ----> cannot be used, it should be v = a x t
6. vf = at + vi ---> can be used
7. a = delta v over t ----> can be used
So the equation that can be used to find acceleration is
1,4,6 and 7
The distance of the elevator
resultant velocity
the average velocity
Answer:
The correct option is 3.
Step-by-step explanation:
The given numbers are
0.3, 0.029, 0.003, 0.01
If we compare two or more numbers then the extreme left are compared. The one having the greater extreme left digit will be greater.
Compare first two numbers.
0.3 > 0.029
Now compare third number with smaller value.
0.029 > 0.003
Now compare fourth number with smaller value.
0.01 > 0.003
The number 0.003 is smaller than 0.3, 0.029 and 0.01.
Since 0.003 is least value. Therefore the correct option is 3.