MATHEMATICS HIGH SCHOOL

Let f(x) = 2x, g(x) = x2 + 2, and h(x) = -4x + 3. Find the composite function.

Answers

Answer 1
Answer:

The compositefunction gof (x) is 4x^2 + 2.

The correct option is b.

What is a composite function?

Let the two functions f(x) and g(x) generate a new function h(x) using an operation.

The operation is a composition of functions and h(x) is a compositefunction.

Given:

Three functions  f(x) = 2x, g(x) = x² + 2, and h(x) = -4x + 3.

To find the compositefunction gof (x), we need to substitute g(x) into f(x) wherever there is an x in f(x).

gof (x) = g(f(x))

= g(2x)

= (2x)²+ 2

= 4x² + 2

Therefore, gof (x) =  4x² + 2.

To learn more about the composite function;

brainly.com/question/29048585

#SPJ7
Answer 2
Answer: (g\circ f)(x)=g(f(x))\n\n(g\circ f)(x)=(2x)^2+2=4x^2+2 \Rightarrow B

Related Questions

Mark works at a popular electronics retail store. He earns a fixed income of $18 an hour and a 5% commission on the sales he makes. Let's say, y = earnings h = number of hours worked s = amount of sales Which of these equations correctly indicates how much Mark earns in a day?
Select the table that represents a linear function. (Graph them if necessary.) Please help!
67.935 in expanded form in fraction form after the decimal
If lines l and m are parallel, then 2 and 3 are corresponding angles.True or false
Which statement best explains why the graphed relation is not a function? A) There are infinitely many points on the graph. B) The domain of the graph does not include all real numbers. C) There are points on the graph with the same x-coordinate but different y-coordinates. D) The graphed relation is not a line.

(2ײ -׳-18ײ-7÷(×+2)
i need solution and explanation​

Answers

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The quotient is equal to :

  • - {x}^(2) - 14x + 28

remainder :

  • - 63

Solution is in attachment ~

Answer:

{ \rm{( {2x}^(2) - {x}^(3) - 18 {x}^(2) - 7) / (x + 2) }}

• now, (x + 2) is the factor.

• let's find the value of xfrom the factor:

{ \rm{x + 2 = 0}} \n { \underline{ \rm{ \: \: x = - 2 \: \: }}}

• let's substitute for xinto the quotient:

{ \rm{f(x) = {2x}^(2) - {x}^(3) - {18x}^(2) - 7 }} \n \n { \rm{f( - 2) = 2 {( - 2)}^(2) - {( - 2)}^(3) - 18 {( - 2)}^(2) - 7 }} \n \n { \rm{f( - 2) = 8 +8 - 72 - 7}} \n \n { \boxed{ \boxed{ \pmb{answer \: \dashrightarrow \: \: {}^( - ) 63 \: \: }}}}

A spherical ballon with a radius r inches has volume V(r)=4/3 pir^3. Find a function that represents the amount of air required to inflate the balloon from a radius inches to a radius of r+1 inches.

Answers

Answer:

The function that represents the amount of air is \Delta V =\cfrac 43 \pi (3r^3+3r+1)

Step-by-step explanation:

The amount of air here represents the difference between V(r) and V(r+1), so we can start working by finding an expression for the volume at r+1, and then subtract the original volume V(r).

Volume of balloon of radius r+1 inches.

We can replace r with r+1 on the formula and we get:

V(r+1)=\cfrac43 \pi (r+1)^3

We can expand (r+1)^3 since we will use it to simplify it later on.

So we will have first

(r+1)^2 = (r+1)(r+1)\n(r+1)^2 =r^2+r+r+1\n(r+1)^2 = r^2+2r+1

We can multiply that result by (r+1) to get (r+1)^3

(r+1)^3= (r+1)^2 (r+1)\n(r+1)^3=(r^2+2r+1)(r+1)\n(r+1)^3= r^3+2r^2+r+r^2+2r+1\n(r+1)^3 =r^3+3r^2+3r+1

Thus the volume equation at r+1 will be

V(r+1)=\cfrac 43 \pi (r^3+3r^2+3r+1)

Finding the amount of air required to inflate from r to r+1

The amount required to inflate is the difference of volumes, so we have

V(r+1)-V(r)=\cfrac 43 \pi (r^3+3r^2+3r+1)  \cfrac 43 \pi r^3

Combinging both into one term by factor \cfrac 43 \pi give us

V(r+1)-V(r)=\cfrac 43 \pi (r^3+3r^2+3r+1-r^3)

Simplifying

V(r+1)-V(r)=\cfrac 43 \pi (3r^2+3r+1)

And that function represents the amount required to inflate the balloon from r  to r+1 inches.

Identify the terms and like terms in the expressionQ + 4 + 2t - 9+ +
Which statements are true? Check all that apply
The expression contains seven terms.
The terms in the expression are a?, 4,21, 9, and .
The constants, 4 and 9, are like terms.
Like terms have the same variables to the same
powers
9, 21, and I are variables, so they are like terms.
2t and t are like terms.

Answers

Answer:

The answer is 2,3,4,6

Step-by-step explanation:

Here is proof! Hope you pass<33

Answer:

2nd option is correct as it has represented all the terms of the expression.

Which steps should be followed to write an equivalent ratio to find 2% of 6700? Write 2% as the ratio StartFraction 200 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(67) = 6700, so (20)(67) = 1340. Write 2% as the ratio StartFraction 20 Over 100 EndFraction. Write the equivalent ratio StartFraction 6700 Over question mark EndFraction. (20)(335) = 6700, so (100)(335) = 33,500. Write 2% as the ratio StartFraction 2 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(67) = 6700, so (2)(67) = 134. Write 2% as the ratio StartFraction 2 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(6.7) = 6700, so (20)(6.7) = 13.4

Answers

Answer:

Step-by-step explanation:

To evaluate the expression 2% 0f 6700, we can follow the steps;

2% = 2/100

6700 = 67(100)

2% of 6700 = 2/100 * 67(100)

The 10 at the numerator will cancel out that at the denominator

2/100 * 67(100) = 2(67)

2(67) = 134

Answer:

Write 2% as the ratio 2/100. Write the equivalent ratio_?_ . (100)(67)= 6700, so (2)(67)=134

6700

Step-by-step explanation: Just did it on edg 2020. IF THIS HELPS IT IS C.

Hurry! You work at a campus book store and a customer needs a textbook that you do not have in stock. You can order the textbook from Campus Corner for $129.95, prior to a rebate of $9.00. Books R Us sells the same textbook for $145.00, prior to a discount of 15%. What is the percent difference in the final cost of the two items?

O 0.018%

O 0.019%

O 1.87%

O 1.90%

O 2.10%​

Answers

Answer:

.187

Step-by-step explanation:

Ninety percent of the ninth grade students at Richbartville High School take algebra. If 180 ninth grade students take algebra, how many ninth grade students do not take algebra? Please give answer and explain how to do it I'm so confused!

Answers

Let the total number of students be x.

Now, according to your question, 90% of x  =  180

= 90/100 * x = 180

90x = 18000

Thus, x = 18000/90

= 200.

Thus, the total number of students are 200. Out of these, 180 are taking algebra. Thus, 20 students are not taking algebra.
Other Questions
Sarah is twice as old as her youngest brother if the difference between their ages is 15 years how old is her youngest brother
What are the factors of 6tu
Ursulla has overdrawn her account by $45. Initially she had $130. How much money did she withdraw from her account?
Your fuel expense for last year was $800.00. This year it was $960.00. What was your percent of increase? A. 20% B. 18% C. 15% D. 23%