Therefore , the solution of the given problem of unitary method comes out to be the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.
The job can be completed by bringing together what was learned and applying this variable technique, that also includes all supplementary data from two people that utilized a specific tactic. To put it another way, if the desired outcome materialises, either the entity stated in the calculation will be recognised, or both expression essential processes will truly skip the colour. For forty pencils, a refundable charge of Rupees ($1.01) might be required.
Here,
Using the following formula, one can determine the conditional chance that a child will have a curfew if they have chores:
Curfew and duties are equal, so
=>P(curfew | chores) = P (chores)
The odds are listed in the table below:
=> Curfew and errands P = 3/10
=> P(tasks) = 7/9
Therefore,
=> P(curfew | chores)=3/10/ (7/10)=3/7
Therefore, the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.
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Answer:
d = 8
Step-by-step explanation:
Given
8 + 4d = 5d ( subtract 4d from both sides )
8 = d
Answer:
d=8
Step-by-step explanation:
8+4d=5d
1. subtract 8 from both sides > 8+4d-8=5d-8
2. simplify > 4d=5d-8
3. subtract 5d from both sides > 4d-5d=5d-8-5d
4. simplify again > -d = -8
5. divide both sides by -1 > -d/-1 = -8/-1
6. simplify again > d=8