The number of guests in a hotel per day resembles a normal distribution with a mean of 220 and standard deviation of 30. One day, the z-score of the number of guests was 2.3. How many guests did the hotel have on that day?
Answers
The hotel had 289 guests on the day in question. The z-score is a measure of how many standard deviations a data point is away from the mean of the distribution.
In this case, we are given that the number of guests in a hotel per day follows a normal distribution with a mean of 220 and a standard deviation of 30, and that the z-score of the number of guests on a particular day was 2.3.
Using the formula for z-score, we have:
z = (x - mu) / sigma
where x is the number of guests on the given day, mu is the mean of the distribution, and sigma is the standard deviation of the distribution.
Substituting the given values, we have:
2.3 = (x - 220) / 30
Multiplying both sides by 30, we get:
69 = x - 220
Adding 220 to both sides, we get:
x = 289
Therefore, the hotel had 289 guests on the day in question.
Find out more about standard deviations
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Base on the given choices, you can afford all prices but practicality wise, 441.47 dollars is the most recommended rentals.
Answer with explanation:
We will use , rule here, which states that , 28 % of your monthly income should be used for housing finances and 36 % of your total gross income should be used for debt purposes.
Total Annual Salary = $ 18,920
Monthly salary
→→28% of 18,920
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Answers
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