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A circle with a diameter of 36 inches is shown.circle with diameter of 36 inches

What is the area of the circle using π = 3.14?

113.04 in2
452.16 in2
1,017.36 in2
4,069.44 in2

Answers

Answer 1
Answer:

Answer:

1017.36 in²

Step-by-step explanation:

Information we need to know:

Radius = diameter ÷ 2

Area of circle = πr²

1) Find the radius of the circle

We have to make sure the we are using the radius of the circle instead of the diameter as the formula using the value of r. If we were to use the diameter our answer would be wrong.

  • 36 ÷ 2 = 18

2) Find the area

To find area we can distribute the numbers given into the formula...

  • 3.14 (π) x 18 (r)² = 1017.36

Hope this helps, have a lovely day! :)
Answer 2
Answer: Answer:

A = 1,017.36 in²
The answer is option C

Step by step solved:

The formula to calculate the area of a circle is

A = πr²,

where A is the area and r is the radius of the circle. In this case, the diameter of the circle is given as 36 inches, so the radius is half of that, which is 18 inches.

Using the value of π as 3.14, we can plug in the values and calculate the area as follows:

A = πr²
A = 3.14 x 18²
A = 3.14 x 324
A = 1,017.36 in²

Therefore, the area of the circle with a diameter of 36 inches using π = 3.14 is 1,017.36 in². The answer is option C

Related Questions

If f(x) = -1/x, then f'(x) = 1/x^2. Theorem seems to suggest that the integral from -1 to 1 of 1/x^2 dx would equal f(1) - f(-1) = -1 -1 = -2. But 1/x^2 is a positive function and so its integral over [-1,1] should be positive. What is wrong here?
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What are the answers to 7 and 8?
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If AB = 3, AD= 5, andDE= 6, what is the length of BC?

Determine which statements are true in the set of real numbers3. (Select all that apply.) (a) Two lines parallel to a third line are parallel. (b) Two lines perpendicular to a third line are parallel. (c) Two planes parallel to a third plane are parallel. (d) Two planes perpendicular to a third plane are parallel. (e) Two lines parallel to a plane are parallel. (f) Two lines perpendicular to a plane are parallel. (g) Two planes parallel to a line are parallel. (h) Two planes perpendicular to a line are parallel. (i) Two planes either intersect or are parallel. (j) Two lines either intersect or are parallel. (k) A plane and a line either intersect or are parallel. Incorrect: Your answer is incorrect.

Answers

Answer:

(a) True

(b) False

(c) True

(d) False

(e) False

(f) True

(g) False

(h) True

(i) True

(k) True

Step-by-step explanation:

(a) Two lines parallel to a third line are parallel

True

(b) Two lines perpendicular to a third line are parallel

Only for  lines on the same plane

Therefore, false

(c) Two planes parallel to a third plane are parallel

True

(d) Two planes perpendicular to a third plane are parallel

The two planes can be at an angle to each other and so intersect

Therefore, false

(e) Two lines parallel to a plane are parallel

Where the two lines are on a plane parallel to the first plane but the lines are not themselves parallel to each other they intersect

Therefore, false

(f) Two lines perpendicular to a plane are parallel

True

(g) Two planes parallel to a line are parallel

Where the planes are not parallel to each other, they will intersect

Therefore, false

(h) Two planes perpendicular to a line are parallel

True

(i) Two planes either intersect or are parallel

True

(k) A plane and a line either intersect or are parallel

True.

A line has a slope of $-7$ and contains the point $(3,0)$. The equation of this line can be written in the form $y = mx+b$. What is the value of $m+b$?

Answers

Answer:

  14

Step-by-step explanation:

In point-slope form, the equation with slope -7 through point (3, 0) can be written ...

  y = -7(x -3) +0

  y = -7x +21 . . . . . eliminate parentheses

Here, we can see m=-7 and b=21, so ...

  m+b = -7+21 = 14

Final answer:

The equation of the line is y = -7x + 21, and the value of m + b is 14.

Explanation:

The equation of a line can be written in the form y = mx + b. In this form, m represents the slope of the line and b represents the y-intercept. Since the slope of the line is given as -7, we can substitute -7 for m. The line also contains the point (3,0), which means that when x = 3, y = 0. Plugging these values into the equation, we can solve for b:

0 = -7(3) + b

0 = -21 + b

b = 21

Therefore, the value of m + b is -7 + 21 = 14.

Learn more about Equation of a line here:

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In the equation (y-7)=(3)/(4)(x-5) a point on that line is1.(-5,-7)
2.(7,5)
3.(-7,-5)
4.(5,7)

Answers

Answer:

First find the slope of the straight line, m=(Y2-Y1)/(X2-X1)=(17–7)/(-5–0)=-2.

Using the standard equation of a straight line, y=mx+b, we know that m=-2.

Thus, so far we know that y=-2x+b.

Now plug in the coordinates of either of the above points, that we know do lie on the straight line, into our equation, y=-2x+b, and solve for b.

I will use the first point, (0,7), to get 7=(-2)(0)+b.

Solving for b, we see that b=7.

Therefore, the equation of the straight line is y=-2x+7.

It is a good idea to check your answer on a graphing calculator.

The equation 2|3x−1|=10 has two solutions, one positive and one negative. Solve the equation to find the solutions.

Answers

The two solutions of the equation 2|3x - 1| = 10 are x = 2 and

x = -4/3.

We have the following equation -

2|3x -1| = 10

We have to solve the equation to find the solutions.

What is modulus function ?

The modulus function is as follows -

for x > 0 , |x| = x

for x < 0 , |x| = - x

According to the question, we have -

2|3x - 1| = 10

|3x -1| = 5

Now, using the modulus property -

3x - 1 = 5       and       3x - 1 = -5

3x = 6        and       3x = -4

x = 2          and        x = -4/3

Hence, the two solutions of the equation 2|3x - 1| = 10 are x = 2 and

x = -4/3.

To learn more about Modulus function, visit the link below-

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1/3 x− 1/8 y=3
7y+9x=−2
please solve the system
45 points for who does

Answers

Answer:

x=6\ny=-8

Step-by-step explanation:

(1)/(3)x-(1)/(8)y=3\n 7y+9x=-2

One method could be rewriting the second equation as x in terms of y and solving by replacing in the first equation.

7y+9x=-2\n9x=-2-7y\nx=(-7y-2)/(9)

Replace...

(1)/(3)x-(1)/(8)y=3

(1)/(3)((-7y-2)/(9))-(1)/(8)y=3

(-7y-2)/(27)-(1)/(8)y=3

-(7)/(27)y-(2)/(27)-(1)/(8)y=3

add (2)/(27) on both sides.

-(7)/(27)y-(1)/(8)y=3+(2)/(27)

Combine like terms

((-7)(8)-(1)(27))/((27)(8)) y=((3)(27)+2)/(27)

(-56-27)/(216) y=(81+2)/(27)

(-83)/(216)y =(83)/(27)

Now, to get rid of the fraction and isolate y, multiply by the reciprocal or the inverted fraction.

((216)/(-83)) (-83)/(216)y =(83)/(27)((216)/(-83))

y=(216)/(-27)

Simplify

y=-8

Now replace the value of y in either equation to find x.

7y+9x=-2\n7(-8)+9x=-2\n-56+9x=-2

add 56

56-56+9x=-2+56\n9x=54\n

Divide by 9

(9x)/(9)=(54)/(9)\n x=6

To check whether these values are accurate, replace in either equation both values and you should have an equality. In this case I'll do it in both equations.

(1)/(3)x-(1)/(8)y=3

(1)/(3)(6)-(1)/(8)(-8)=3

2-(-1)=3\n2+1=3\n3=3

-----------------------------------------------------------------

7y+9x=-2\n7(-8)+9(6)=-2\n-56+54=-2\n-2=-2

(9c^2 + 3c + 9) - (9c^2 + 2c + 7)

Answers

Answer:

c+2

Step-by-step explanation:

Distribute the Negative Sign:

=9c2+3c+9+−1(9c2+2c+7)

=9c2+3c+9+−1(9c2)+−1(2c)+(−1)(7)

=9c2+3c+9+−9c2+−2c+−7

Combine Like Terms:

=9c2+3c+9+−9c2+−2c+−7

=(9c2+−9c2)+(3c+−2c)+(9+−7)

Answer:

c + 2

Step-by-step explanation:

(9c² + 3c + 9) - (9c² + 2c + 7)

9c² + 3c + 9 - 9c² - 2c - 7

9c² + 3c + 9 - 9c² - 2c - 7

c + 2
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