Give the z test statistic and its P-value. What do you conclude about the authorship of the new poems? (Let a = .05.)
Use 2 decimal places for the z-score and 4 for the p-value.
a. What is z?
b.The p-value is greater than?
c.What is the conclusion? A)The sonnets were written by another poet or b) There is not enough evidence to reject the null.
Answer:
We conclude that the sonnets were written by by a certain Elizabethan poet.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 8.9
Sample mean, =10.2
Sample size, n = 6
Alpha, α = 0.05
Population standard deviation, σ = 2.5
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Formula:
Putting all the values, we have
Now,
b) We calculate the p value with the help of z-table.
P-value = 0.1003
The p-value is greater than the significance level which is 0.05
c) Since the p-value is greater than the significance level, there is not enough evidence to reject the null hypothesis and accept the null hypothesis.
Thus, we conclude that the sonnets were written by by a certain Elizabethan poet.
The z-score is 1.86 and the p-value is 0.0314. As the p-value is less than the level of significance α (0.05), we reject the null hypothesis and conclude that the new sonnets were likely written by another author.
In this statistical testing scenario for authorship of literary works, we need to find out the z-score or z test statistic and then determine the p-value to check if the new sonnets could be the works of the known Elizabethan poet or not.
For calculating the z score, you use the formula z = (x~ - μ) / (σ / √n) = (10.2 - 8.9) / (2.5/ √6) = 1.86 to two decimal places. The p-value is determined from the standard normal distribution table which for a z-score of 1.86 is 0.0314.
Given that α = 0.05, since the p-value is less than α, we reject the null hypothesis H0 (that the works were by the Elizabethan poet). Therefore, we accept the alternative hypothesis Ha (the sonnets were written by another author).
#SPJ3
13 + 16y
B
16 + 104y
C
104 + 16y
D.
104 + 2y
Answer:
c
Step-by-step explanation:
Answer:
she develops a fair and healthy relationship with her classmate but also she elected the class president at their school
Step-by-step explanation:
vote me as the brainliest
City B: {5, 6, 3.5, 5.5, 4, 6}
(a) What is the mean monthly rainfall amount for each city?
(b) What is the mean absolute deviation (MAD) for each city? Round to the nearest tenth.
(c) What is the median for each city?
Answer:
City A: {2, 3.5, 4, 4, 5, 5.5}
City B: {3.5, 4, 5, 5.5, 6, 6}
Mean is the average.
Average of City A = 4 (2+3.5+4+4+5+5.5 = 24 and 24/6 = 4)
Average of City B = 5 (3.5+4+5+5.5+6+6 = 30 and 30/6 = 5)
Mean Absolute Deviation
Mean Absolute Deviation of City A = 0.8
Mean Absolute Deviation of City B = 0.8
Median is the middle (after putting it in order least to greatest)
Median of City A = 4
Median of City B = 5.25 (5+5.5 = 10.5 and 10.5/2 =5.25)
Step-by-step explanation:
hope this helps!