Jordans have a rectangular garden. want to build a diagonal pathway across he garden. the length of pathway is 90 ft. width of garden is 5 times more than 2 times the length of garden. what is length of garden?

Answers

Answer 1

Answer: so we see the pythagorean theorem
a^2+b^2=c^2
diagonal=c
width=a or b, pick one
width=a
legnth=b
width is 5 times more than 2 times legnth of garden
w=5(2legnth)
this doesn't make sense since the legnth is normally longer than the width, but we'll stick with that
w=5(2l)
w=10l
a=10b
(10b)^2+b^2=90^2
100b^2+b^2=8100
101b^2=8100
divide by 101
b^2=80.198 aprox 80.2
square root
8.95533
legnth of garden =8.96
to find width subsitue
w=10l
w=89.56

legnth=8.96
width=89.56

Answer 2

Answer: P=2l+2w
w=5(2l)
45=10l
4.5=l
---------------
P=2l+2(5(2l))
P=2l+20l
P=22l
P=99

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Answers

Your answer is the second one

Answer:

i think it might be D) 9x(4xy^2 − y^2)

Step-by-step explanation:

The data set represents the number of rings each person in a room is wearing.0, 2, 4, 0, 2, 3, 2, 8, 6

What is the interquartile range of the data?

2
3
4
6

Answers

Answer:

the interquartile range of the data is:

Step-by-step explanation:

We are given a data set as:

0, 2, 4, 0, 2, 3, 2, 8, 6

On arranging the data in the ascending i.e. increasing order is given by:

0 0 2 2 2 3 4 6 8

The minimum value of data set=0

Maximum value of data set is: 8

Range of data set= Maximum value-Minimum value

i.e. Range= 8-0

i.e. Range= 8

Also, Median of set is the central tendency of the data and is given by:

Median= 2

Lower set of data is:

0 0 2 2

Hence, The median of lower set of data is the lower quartile or first quartile.

i.e. $Q_1$

Hence, $Q_1=(0+2)/(2)\n\n\nQ_1=(2)/(2)\n\n\nQ_1=1$

Hence, Lower quartile=1

Similarly upper set of data is:

3 4 6 8

Hence, The median of upper set of data is the upper quartile or third quartile.

i.e. $Q_3$

Hence, $Q_3=(4+6)/(2)\n\n\nQ_3=(10)/(2)\n\n\nQ_3=5$

Hence, Upper quartile=5

Hence, the interquartile range(IQR) is given by:

IQR=Upper quartile-Lower quartile

IQR=5-1

IQR=4

If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.

Factor out the greatest common factor. If the greatest common factor is 1, just retype the polynomial.2b4+5

Answers

In this case, the greatest common factor IS 1;

There is no number or variable that divides evenly into both 2b^4 and 5, so you leave it as 2b^4 + 5.

The ratio of men to women in a certain factory is 3 to 4. There are 222 men. How many workers are there?

Answers

The ratio of men to women in a certain factory = 3:4
The total number of men in the factory = 222
Let us assume the common ratio to be = x
Then
3x = 222
x = 222/3
= 74
Then
The total number of women workers in the factory = 4 * 74
= 296
So
The total number of workers in the factory = 296 + 222
= 518
From the above deduction we can easily conclude that there are a total of 518 workers in the factory.

Write the following in decimals twelve and nine thousand six hundred and forty-seven millionths

Answers

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The tax rate is 7.5% What is the tax on 110?

Answers

The answer is 8.25

110/x=100/7.5
(110/x)*x=(100/7.5)*x -
110=13.333333333333*x -
(13.333333333333) to get x
110/13.333333333333=x
8.25=x
x=8.25

110 * .075 = 8.250
8.25 = 8.30
The tax on 110 is 8.30.

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