The given substance combusts following the reaction:
C2H2 + (5/2)O2 -> 2CO2 + H2O
Assume C2H2 is an ideal gas. At STP, 1 mol of an ideal gas occupies 22.4 L. Given 100.50 mL of C2H2, this means that there is 4.4866 x 10^(-3) mol. Combusting 1 mol of C2H2 consumes (5/2) mol of O2, then combusting the given amount of C2H2 consumes 0.01121 mol of O2. At STP, this amount of O2 occupies 251.25 mL.
Answer: 251.25 ml
Explanation:
According to Avogadro's law, 1 mole of every gas occupies 22.4 L at Standard temperature and pressure (STP).
2 moles of occupy =
5 moles of occupy =
Thus 44800 ml of reacts with 112000 ml of at STP
100.50 ml of reacts with = of at STP.
The statement that is given above “When a system performs work on the surroundings, the work is reported with a negative sign” is true. When the surrounding performs work by the system, it is positive.
(2) metallic crystals
(3) nonpolar molecules
(4) polar molecules
At standard pressure, a certain compound has a low boiling point and is insoluble in water. At STP, this compound most likely exists as nonpolar molecules. Hence, option C is correct.
A molecule in which the individual dipoles cancel each other & result in zero net dipole moment is called a non-polar molecule.
Nonpolar molecules make weak attractions between molecules called van der Waals forces and they are loosely bound with each other.
Therefore, nonpolar molecules can easily go to the atmosphere by breaking those weak bonds and having a boiling point low.
Hence, option C is correct.
Learn more about the nonpolar molecules here:
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Answer is (3) - nonpolar molecules.
Nonpolar molecules make weak attractions between molecules called van der Waals forces. Hence, they are looesly bound with each other. Therefore, nonpolar molecules can easily go to the atmosphere by breaking those weak bonds. Hence, the boiling point is low.
Since water is a polar solvent, nonpolar molecules do not soluble in water.