Answer:
7π mm
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Answer:
y = 12x + 8y
Step-by-step explanation:
The growth of the bacteria is represented by the exponential growth equation. Given the initial population, the four-fold increase, and the time interval for the increase, we can find the population after any given time by using the equation P = 200 * 4^(t/2.5).
The problem given is an example of an exponential growth problem. For these types of problems, we use the formula P = P0 * e^(kt), where P is the final population, P0 is the initial population, k is the growth rate, and t is time. However, in this case, we were given that the bacteria quadruples, meaning 'quadrupling' is not a continuous rate, so we use a slightly different form of the equation: P = P0 * (b)^(t/t0), where b is the times increase and t0 is the time interval for the b-fold increase.
Given that the initial population P0 is 200 bacteria, b is 4 because the population quadruples every 150 minutes, and time t0 is 150 minutes or 2.5 hours. We need to find the population P after t hours. Substituting these values into our equation gives us: P = 200 * 4^(t/2.5).
So, after t hours, the population of the bacteria will be given by the equation P = 200 * 4^(t/2.5).
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Answer:
use a algebra caculator
Step-by-step explanation:
Answer:
-4.125
Step-by-step explanation:
5/8 - 3/4 (8-1/2 ) + 1 = - 33/8 = -4 1/8