will the pressure be the same on both or will one be greater
Answer: W = 3500 J
Explanation: Work is the product of the amount of force and the perpendicular distance or W = Fd.
W = Fd
= 1400 N ( 2.5 m )
= 3500 J
Answer:
Force = 1400N
Displacement = 2.5 m
work done = F×D
=1400×2.5
= 3500 joule
Answer:
1.
2.
Explanation:
1. Electrostatic force is given as:
where k = Coulombs constant
q = charge of first charge
Q = charge of the second charge
r = distance between them
From the question:
F = 100 N
q =
r = 0.01 m
We need to find Q.
From the formula of force, we have that Q is:
This is the charge, Q, of the second charge.
2. From the question:
F = 2 N
q =
r =
We need to find Q.
Using the same formula for Q as in 1. above, we have that:
This is the charge, Q, of the second charge.
Answer:
(1)
(2)
Explanation:
Force Between two charges is give by.
, here k is called coulomb constant and has value = .
(1) case, F =100N, r = 0.1m and = substituting these values in above equation and solving for unknown gives us.
.
(2) Case, F = 2N, r = and .
again by substituting these in above equation and solving for unknown gives us.
The image is virtual and larger than the object.
The image is virtual and smaller than the object.
The image is real and larger than the object.
Answer:
The image is virtual and smaller than the object.
Explanation:
A concave lens is a diverging lens, meaning that it spreads out light rays that have been refracted through it. A concave lens is thinner at its center than at its edges.
It always produces virtual images because the image appears to form on the same side of the lens where the object is placed.
The image is always smaller than the object. Far the object, smaller will be its image.
A light ray diagram of a concave lens is attached for a better understanding.
Answer: The image is virtual and smaller than the object.
Explanation:
4 J
B.
40 J
C.
400 J
D.
4000 J
The correct answer to the question is C) 400 J.
CALCULATION:
As per the question, the force applied on the block F = 40 N.
The distance travelled by the block S = 10 m.
We are asked to calculate the work done by the block.
The work done by a body under a force F is calculated as -
Work done W =
=
Here, is the angle between force and displacement.
If , then work done W =
= FS. [ cos0 = 1]
Hence, the work done by the block W = FS
= 40 N × 10 m
= 400 Joule. [ans]
Here, Joule is the unit of work.
Hence, the work done by the block s 400 Joule.