a) function is positive on (-∞,-5)
b) fuction is negative on (-5,3)
c) function is positive on (-∞,1)
d) function is negative on (3,∞)
Answer:
d) function is negative on (3,∞)
Step-by-step explanation:
The even degree and negative leading coefficient tell you that the function is negative as x ⇒ ±∞. (Selections A and C cannot be correct.)
The odd multiplicity tells you the function crosses the x-axis at x=-5 and x=3, so will be non-negative between those values. (Selection B cannot be correct.)
The function is negative on (3, ∞).
Answer:
The graph of the function is positive on (-co, -5).
The graph of the function is negative on (3,co).
Step-by-step explanation:
We know that the roots are in: -5, 1 and 3.
and after 3, the graph is in the negative side, so between 1 and 3 the graph must be in the positive side, between -5 and 1 the graph must be in the negative side, and between -inifinity and -5 the graph must be in the positive side:
So the statements that are true are:
The graph of the function is positive on (-co, -5).
The graph of the function is negative on (3,co).
(Points : 5)
-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b)
When Ivan divides his coins into groups of 2 nickels and 1 quarter, worth $0.35, he find that he has $8.75/$0.35 = 25 such groups.
Ivan has 25 quarters and 50 nickels.
Let n denote the number of nickels.
and q denote the number of quarters.
1 nickel=0.05 dollar
and 1 quarter=0.25 dollar
Hence, we have:
0.05n+0.25q=8.75
( Since, Ivan has $8.75 in nickels and quarters in his desk drawer )
On multiplying both side of the equation by 100 we have:
5n+25q=875
on dividing both side of the equation by 5 we have:
n+5q=175-----------------(1)
Also, n=2q---------------(2)
( Since, the number of nickels is twice the number of quarters )
Hence, on putting equation (2) in equation (1) we have:
2q+5q=175
i.e.
7q=175
i.e. q=25
and on putting the value of q in equation (2) we have:
n=50