Prove that 1 - cosx / sinx = sinx / 1 + cosx
how?

Answers

Answer 1
Answer:

Answer:

see explanation

Step-by-step explanation:

using the identity

cos²x = 1 - sin²x

consider the left side

(1-cosx)/(sinx)

multiply numerator/ denominator by (1 + cosx)

= ((1-cosx)(1+cosx))/(sinx(1+cosx)) ← expand numerator

= (1-cos^2x)/(sinx(1+cosx))

= (sin^2x)/(sinx(1+cosx)) ← cancel sinx on numerator/ denominator

= (sinx)/(1+cosx)

= right side , thus proven


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Max started a trip with of a tank of gas. At the end of his trip, Max had of a tank left. How much gas did Max use on the trip?

Answers

Answer:

None or all of it and he the refilled but it's probably none

Step-by-step explanation:

Because his final product is the same as his starting point

Nolan plots a point at (0, 3) on the y-axis. He uses a slope of 2 to graph another point. He draws a line through the two points. Which equation represents Nolan’s line?

Answers

Equation of a line passing through a point is given by: (y - y1)/(x - x1) = m. where m is the slope.
Hence, we have
(y - 3)/x = 2
y - 3 = 2x
y = 2x + 3

Answer:

B. y = 2x + 3

Step-by-step explanation:

did it on edge 2020

Identify the asymptotes.
y=1/x-6

Answers

Horizontal asymptote
y=1x−6

limx→∞
=1/x−6

=(1/x) / [(x/x)−6/x]

 

=0 / 1

= 0

The function is also undefined at x=6. So there is a vertical asymptote at x=6.

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How u write an inequality for brigitte is shorter than 5 feet (brigitte height =h)

Answers

Since Brigitte in shorter or lesser than 5 feet, h ges on the right of the lesser than symbol.
5 < h

If amanda hikes at an average speed of 2.72 miles per hour, how long will it take her to hike 6.8 miles

Answers

i hope this helps you

Write the equation of the line, given the y- and x-intercepts. x-intercept (–6, 0), y-intercept (0, –8)

Answers

neverminding for a second that they're intercepts at all, they're points on the line, so


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{-8})\n\n\n slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-0}{0-(-6)}\implies \cfrac{-8-0}{0+6}\implies \cfrac{-8}{6}\implies -\cfrac{4}{3}\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-0=-\cfrac{4}{3}[x-(-6)]\n\n\ny=-\cfrac{4}{3}(x+6)\implies y=-\cfrac{4}{3}x-8