1) 3x +y=23 try to label them one and two.
2)3x -2y=8 First lets find the x. To do that we have to changed the y,and find the common number fo them.
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1) 3x+y=23 try to times the whole equation number 1) by 4, and equation 2) by 2.
2) 3x-2y=8
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1) 12x+4y=92 That's how the euation should look after you would times it.
2) 6x-4y=16 Then add them.
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12x +6x = 18x ..... 4y+4y_ this won't have to be solved at we only had to times it so we could eliminate does y's as we only wanted to find out x.
92+16=108
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So then we have...
18x = 108 This means we have to divide 108 by 18 to find out x.
108/18 = 6.
x=6.
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To find y we have to do the same method but we have to eliminate x, by findin a common number in x's.
1) 3x+y=23 Try to time the two equations by 2.
2)3x-2y=8
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1) 6x+2y=46 Yoou should get something like that. Then add them.
2) 6x-4y=16
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6x+6x_ we won't gonna add them as we only had to multiply them to get the same answer to eliminate these.
2y+ -4y= -2y ............. 46+16=62
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So it should be: 2y=62
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No we only have to divide 62 by 2, which is 31
so y=31.
Answer:
y = -3x + 9 is your answer.
Step-by-step explanation:
So your y-intercept is the slope. Here is the equation we are going to use:
y - y_1 = m(x - x_1)
y_1 = 0
x_1 = 3
m = -3.
y - 0 = -3(x - 3)
y - 0 = -3x + 9
y = -3x + 9 is your answer.
The standard form of the line is y = x - 3.
To find the standard form of a line, we need two pieces of information: the slope of the line and a point on the line. Given that the line has a y-intercept of -3, we know that the y-coordinate is equal to -3 when the x-coordinate is 0. So, we have the point (0, -3). We also know that the line passes through the point (3, 0). Using these two points, we can calculate the slope of the line:
Slope (m) = (change in y) / (change in x) = (0 - (-3)) / (3 - 0) = 3/3 = 1.
Now that we have the slope and a point on the line, we can use the point-slope form of a line to write the equation:
y - y1 = m(x - x1), where (x1, y1) are the coordinates of a given point and m is the slope of the line.
Substituting the values of (x1, y1) = (3, 0) and m = 1 into the equation, we get:
y - 0 = 1(x - 3)
y = x - 3
Therefore, the standard form of the line that contains a y-intercept of -3 and passes through the point (3,0) is y = x - 3.
#SPJ12
A) 2n
B) n + 3
C) 2n + 1
D) -n + 3
Answer:The answer is D
Step-by-step explanation: for the first term (1)
-(1)+3=2. Whist is the correct number for the 1st term