b. suspensions
c. colloids
d. solutions
The answer is A) heterogeneous mixtures, look up how a heterogeneous mixture is separated and it will tell you distillation. Have a nice day and good luck on the rest of your work
Answer: The correct answer is neutrons.
Explanation:
There are 3 subatomic particles that are present in an atom. They are: protons, electrons and neutrons.
Protons carry positive charge and are found inside the nucleus of an atom.
Electrons carry negative charge and are found around the nucleus in the orbits.
Neutrons does not carry any charge and are found inside the nucleus of an atom.
Hence, the correct answer is neutrons.
(2) chlorine (4) oxygen
Answer: (1) carbon
Explanation: Organic compounds are those compounds which contains a carbon atom. Nearly all organic compounds contain hydrogen and some of the organic compounds contain oxygen. Example: Glucose(), Methane ()
Inorganic compounds are those compounds which do not contain a carbon atom. Example :
An organic compound, by definition, must contain at least one carbon atom. Other elements such as nitrogen, chlorine, and oxygen can also be part of organic compounds, but they're not a requirement. An example of an organic compound is methane, which contains one carbon atom and four hydrogen atoms. The correct option is 1.
An organic compound is a type of molecule characterized by its carbon-based structure. By definition, an organic compound contains at least one carbon atom, which is option (1) in your question.
Although organic compounds can also contain atoms of nitrogen, chlorine, oxygen, and several other elements, these are not a requisite for a compound to be considered organic. The key component, fundamentally speaking, is carbon.
For instance, methane (CH4) is an example of an organic compound. It includes one carbon atom and four hydrogen atoms.
On the other hand, carbon dioxide (CO2), which contains one carbon atom and two oxygen atoms, is not considered an organic compound, even though it contains carbon, because it doesn't contain any carbon-hydrogen bonds, which are typically found in organic compounds.The correct option is 1.
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The experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.
Rutherford's model also called Rutherfords' atomicmodel was a model describing the nuclear atom or the planetary model of the atom. It gave a description of the structure of atoms.
It was proposed the year 1911 by the New Zealand-born physicist named ErnestRutherford. This model was used to describe the atom. It described the atom as tiny and dense which has a positively charged core called the nucleus.
In the nucleus of the atom, almost all the mass is the atom is concentrated. Around the nucleus, there are the light, negative particles which are called electrons. These circulate around the nucleus at some distance like planets revolve around the Sun.
Therefore, the experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.
Read more about atomicmodels, here
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Answer:
Two
Step-by-step explanation:
There are two ways to determine the number sets of equivalent protons in a compound.
(a) By substitution
Replace each H with a different group and see if you get a different compound
For example, the six CH₃ H atoms are an equivalent set, because, if I replace any one of them, I will always get the same compound: 1-chloromethyl-4-methylbenzene (Fig. 1).
Similarly, the four aromatic H atoms are an equivalent set. If I replace any one of them, I will always get the same compound: 2-chloro-1,4-dimethylbenzene (Fig. 2).
Thus, there are two sets of equivalent protons in p-xylene.
(b) By symmetry
Two atoms are equivalent if one can be converted into the other by a symmetry operation on the molecule.
The methyl hydrogens can be interconverted by a combination of reflections about the AB and CD mirror planes and byrotations about the C-C bonds to the ring (Fig. 3).
Similarly, the four aromatic H atoms can be interconverted by a combination of reflections about the AB and CD mirror planes.
Again, we find two sets of equivalent protons.