Which of the following is the function representing the graph below?

Answers

Answer 1

Answer:
You need to pick a point on the graph, then go through the list of choices
and see which one can produce the point you picked.

Look at the point on the graph right above the origin, where the graph
crosses the y-axis. At that point, x=0 and f(x) (or 'y') = 1 .

Now look at the choices, one at a time, and see whether (0, 1) fits.
I'll start at the bottom of the list:

--> f(x) = 4^(x-3)
When x=0, f(x) = 4^(-3) .
4^(-3) is not '1', so our point is not on this f(x).

--> f(x) = 4^x + 3
When x=0, f(x) = 4⁰ + 3 = 1 + 3 = 4
'4' is not '1', so our point is not on this f(x).

--> f(x) = 4^x - 3
When x=0, f(x) = 4⁰ - 3 = 1 - 3 = -2
'-2' is not '1', so our point is not on this f(x).

(Only one choice left.)

--> f(x) = 4^x
When x=0, 4^x = 4⁰ = 1
That's it ! Our point is on this f(x).
Which is lucky, because we were out of choices.

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What is the greatest common factor of the terms in the expression 36a+54ab-27b?

Find the product of 2x4(4x2 + 3x + 1). 8x6 + 6x5 + 2x4

8x8 + 3x4 + 2x4

2x4 + 6x5 + 8x6

6x6 + 5x5 + 3x4

Answers

Answer:

The product of the $2x^(4)(4x^(2)+3x+1)$ is $8x^(6)+6x^(5)+2x^(4)$ .

Step-by-step explanation:

As given the expression in the question be

$= 2x^(4)(4x^(2)+3x+1)$

First open the bracket

$= 2x^(4)* 4x^(2)+2x^(4)* 3x+2x^(4)* 1$

Now by using the property

$x^(a)* x^(b)=x^(a+b)$

$= 8x^(6)+6x^(5)+2x^(4)$

Therefore the product of the $2x^(4)(4x^(2)+3x+1)$ is $8x^(6)+6x^(5)+2x^(4)$ .

$2x^4(4x^2 + 3x + 1)=\n\n(2x^4)(4x^2)+(2x^4)(3x)+(2x^4)(1)=\n\n8x^6 + 6x^5+2x^4$

The answer is A.

Inequalities
x+3 <=10

Answers

Solutions

x+ 3 <= 10

Subtract 3 from each side:

x <= 7

$x+3\leq10\n x\leq7$

What is a radius f a circle with diameter of
240mm

Answers

r=120 mm
diameter 240
so your answer is 120mm

well if you have the diameter then this is simple.
the diameter divided by 2 is the radius..
so 240/2=120
so the radius of the circle should be 120

Which properties can be used to solve 7y − 15 = −29? Select all that apply. A. Identity Property of Multiplication B. Addition Property of Equality
C. Distributive Property
D. Inverse Property of Multiplication
E. Commutative Property of Addition

Answers

The properties that can be used to solve 7y - 15 = -29 are

Addition property of equality and inverseproperty of multiplication.

Given equation is 7y - 15 = -29.

We will solve for y and see which of the given following properties are applied.

What is addition property of equality and the inverse property of multiplication?

Addition property of equality

If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal.

Inverse property of multiplication

It states that every non-zero x multiplied with 1/x will equal 1.

Solve for y.

7y - 15 = -29

We will add 17 on both sides of the equation.

7y - 15 + 15 = -29 + 15

7y = -14

Now, multiply 1/7 into both sides of the equation.

7y / 7 = -14 / 7

y = -2

While solving for y we see that we have to use the addition property of equality and inverse property of multiplication.

Learn more about properties for solving equations here: brainly.com/question/13282104

#SPJ5

Answer:

A and E

Step-by-step explanation:

Other 2 wouldn't make sense

Only definite of A

Addition Property of Equality ----If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal.

Commutative property of addition- changing the order of the numbers we are adding, does not change the sum. Here's an example of how the sum does NOT change, even if the order is changed

What is the simplified form of the expression? 3^3 ×32+12÷4

Answers

3^3=27
27*32=864
864+12=876
876/12=73
73 is your answer

Two numbers have a difference of 0.7 and a sum of 1. what are the numbers?

Answers

In order to determine the value of the numbers, we can set up algebraic equations to solve. For this case, we need to set up two equations since we have two unknown numbers. We do as follows:
let x = first number and y = second number
From the problem statement, we set up equations.
Equation 1 - the numbers have a difference of 0.7
x - y = 0.7
Equation 2 - the numbers have a sum of 1
x + y = 1
Solving for x and y via substitution method,
x - y = 0.7
(1-y) - y = 0.7
1 - 2y = 0.7
-2y = 0.7 - 1 = -0.3
y = 0.15 or 3/20
x - 0.15 = 0.7
x = 0.85 or 17/20
Thus, the two numbers are 0.15 and 0.85.

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