Answer: It's B this will help u
Answer:
16 protons and 19 neutrons
Answer:
8 g
I took the quiz and because the amount doesn’t change
Answer:
The space occupy by the 180.0 g of gold will be 9.32 cm³
Explanation:
Given data:
Mass of gold = 180.0 g
Volume occupy by the gold = ?
Solution:
The given problem will be solved through the density formula.
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
The density of gold from literature is 19.320 g/cm³
Now we will put the values in formula.
19.320 g/cm³ = 180.0 g/ V
V = 180.0 g/ 19.320 g/cm³
V = 9.32 cm³
The space occupy by the 180.0 g of gold will be 9.32 cm³.
(2) Pb(CrO4)2 (4) Pb2(CrO4)3
Lead chromate and lead sulfate are found in the crystal Pb(Cr, S)O₄, which is a changeable solid mixed phase. This material is the end product of a co-precipitation reaction between lead and chrome salts (see the chapter on production and usage for further information). The correct option is 1.
Water does not dissolve lead chromate, which is produced by the double decomposition process. It is also used as a pigment and is referred to as chrome yellow. In a media that has been buffered with a solution of acetic acid and lead acetate, the lead precipitates as chrome.
There may be significant amounts of water-soluble lead compounds in lead chromate pigments. The formula that represents Lead (II) Chromate is PbCrO₄.
Thus the correct option is 1.
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