b. air
c. carbon dioxide
d. carbon
Answer is: b. air.
Homogeneous mixture (air) has the same proporties of its components (nitrogen, oxygen, carbon dioxide) throughout any given sample.
Together, nitrogen (N₂) and oxygen (O₂) by volume account for 99,03% of the gases composing the dry air in the lower atmosphere.
Volume of nitrogen in air is 78,08%.
Volume of oxygen in air is 20,95%.
Together: 78,08% + 20,95% = 99,03%.
True. The balanced equation: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O represents the combustion of ethane (C₂H6).
A substance (often a hydrocarbon) combines with oxygen (O₂) in a combustion reaction, resulting in the major byproducts of carbon dioxide (CO₂) and water (H₂O). According to the equation, four molecules of carbon dioxide (CO₂) and six molecules of water (H₂O) are produced when two molecules of ethane (C₂H₆) and seven molecules of oxygen (O₂) react.
The number of atoms in each element is equal on both sides of the reaction arrow, indicating that the equation is balanced. This guarantees that the law of conservation of mass—according to which, in a chemical reaction, mass is never created nor destroyed—is upheld.
In conclusion, the combustion of ethane is accurately represented by the following balanced equation.
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2C2H6 + 7O2 → 4CO2 + 6H2O
C2H6 is ethane,
Ethane reacts with oxygen, so it is the combustion.
The equation is balanced.
Answer is True.
Answer: P2O5
Explanation: You divide both subscripts by 2 to get the empirical formula.
Answer:
Formula of P4O10 is P2O5.
Explanation:
WE GET IT BY DIVIDING BOTH SUBSCRIPTS BY 2.