a train track runs parallel to a road represented by the equation y=4x+17.A train station along the track is located at the point (6,-1). What is the equation of the line that represents the train track ?

Answers

Answer 1

Answer: y -(-1) = 4(x - 6) <=> y = 4x -27;

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Graphing recorded data from a chart or table would be helpful for interpreting trends or patterns. Please select the best answer from the choices provideda. True b. False
The profit a company earns every month depends of the amount of product sold, p, for $855 each and the amount spent in rent, utilities and other expenses, which always totals to $6,780. The CEO of the company earns 1 this profit. How much the CEO eam if the company sells 250 products in a given month?

Round each number to the nearest tenth. What is the best estimate for the answer to 47.82 74.31?

Answers

i think that you are multiplying them so the answer is 3553.5

and if your adding it would be 122.1

What is the length of stack A G with bar on top in the rectangular prism? Round your answer to the nearest tenth.

Answers

I saw the image that should accompany this problem.
It is a rectangular prism and the base has a right triangle with a measure of the following: long leg = 18cm ; short leg = 16cm

We need to look for the hypotenuse because it serves as the long leg of the right triangle where AG is the hypotenuse.

base triangle
a² + b² = c²
(16cm)² + (18cm)² = c²
256cm² + 324cm² = c²
580 cm² = c²
√580cm² = √c²
24 cm = c

2nd triangle: long leg = 24cm ; short leg = 16cm
(24cm)² + (16cm)² = c²
576 cm² + 256 cm² = c²
832 cm² = c²
√832 cm² = √c²
28.8 cm = c

the length of stack AG is 28.8 cm.

Los Angeles Airport bears 140 degrees from San Francisco Airport and is 540 km away. A pilot is planning a direct flight from San Francisco Airport to Los Angeles Airport to leave at 2 P.M. The plane's air speed will be 640 km/h, and there will be a 60 km/hwind blowing from 290 degrees. What should the compass heading be,and what is the plane's estimated time of arrival (ETA) to the nearest minute?

Answers

Create a triangle starting with the length of 540 coming out of SF to LA bearing 140.
This looks like it leaves SF in IV quadrant and enters LA in II quadrant. The wind will take the plane more to the east (right). Therefore the pilot must aim to the west (left) in order for the wind to push it to the intended destination of LA. The second side of the triangle should come out of LA from the II quadrant bearing 290. The length of this side is 60t (60 km/h * t = time flying). The third side of the triangle connects the first two. There for it comes out of SF at some unknown angle > 140 and connects with the 60t side. The length of this third leg is 640t. (640 km/h * t = time flying). The angle between the 540 side and the 60t side is 30. This is found because the 540 side enters LA in 2nd quadrant as 130 angle . The 60t side enters LA in 2nd quadrant as 160 angle. Using law of sin's: sin 30/640t = sin x/60t. The t's cancel and you are left with sin x = 3/64. When solving for the angle x you get x = 2.6867 degrees. Adding this to the bearing of 140, the compass bearing should be 142.6867 or 142.7 degrees. To find the value of t, you use the law of sin's to get sin 30/640t = (sin (180 - 30 - 2.6867))/540. Solving for t gives you: t = .7811. This is in hours. To convert to minutes multiply by 60 to get t = 46.87 minutes. Add this to the 2pm departure time to get 2:47 pm arrival time.

Camille uses a 20% off coupon when buying a sweater that costs $47.99. If she also pays 6% sales tax on the purchase, how much does she pay?

Answers

The cost of the sweater is given by the equation A = $ 40.69

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the total cost of the sweater be represented as A

Now , the equation will be

The cost of sweater without discount and sales tax = $ 47.99

The discount percentage = 20 %

The cost of sweater after discount = 47.99 - ( 20/100 ) x 47.99

On simplifying the equation , we get

The cost of sweater after discount = 47.99 - 9.598

The cost of sweater after discount = $ 38.392

Now , the percentage of sales tax = 6 %

The cost of sweater after sales tax = 38.392 + ( 6/100 ) x 38.392

On simplifying the equation , we get

The cost of sweater after sales tax = 38.392 + 2.30352

The cost of sweater after sales tax = $ 40.695

Therefore , the value of A is $ 40.69

Hence , the final cost of the sweater is $ 40.69

To learn more about equations click :

brainly.com/question/19297665

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First calculate what the coupon does for Camille
so multiply %20 by the cost or .2(47.99)=9.598 which rounds to 9.60 meaning she still paid $38.39
Then calculate sales tax by multiplying her clearance price by %6 and adding it on the cost
.06(38.39)= 2.3034 which rounds to $2.30 in tax.
Add that onto the clearance price 38.39+2.30=$40.69
So her total cost was $40.69

cards are dealt one by one from a well shuffled pack of 52 cards. find the probability that exactly n cards are dealt before the first ace appears. if the cards are drawn further, then find the probability that exactly k cards are dealt in all before the second ace.

Answers

To find the probability that exactly n cards are dealt before the first ace appears, we can use the concept of a geometric distribution. In a geometric distribution, we're interested in the number of trials (in this case, card draws) required for a success to occur (in this case, drawing an ace) for the first time.

The probability of drawing an ace in a single draw from a well-shuffled pack of 52 cards is 4/52 because there are 4 aces out of 52 cards.

So, the probability of drawing a non-ace in a single draw is (52 - 4)/52 = 48/52.

Now, let X be the random variable representing the number of cards drawn before the first ace appears. X follows a geometric distribution with parameter p, where p is the probability of success on a single trial.

P(X = n) = (1 - p)^(n - 1) * p

In this case, p is the probability of drawing an ace on a single trial, which is 4/52, and n is the number of cards drawn before the first ace.

So, the probability that exactly n cards are dealt before the first ace appears is:

P(X = n) = (1 - 4/52)^(n - 1) * (4/52)

Now, to find the probability that exactly k cards are dealt in all before the second ace appears, we need to consider two scenarios:

1. The first ace appears on the nth card, and the second ace appears on the kth card after that. This is represented by P(X = n) * P(X = k).

2. The first ace appears on the kth card, and the second ace appears on the nth card after that. This is represented by P(X = k) * P(X = n).

So, the total probability that exactly k cards are dealt before the second ace appears is:

P(X = n) * P(X = k) + P(X = k) * P(X = n)

You can calculate this probability using the formula for the geometric distribution with p = 4/52 as mentioned earlier for both P(X = n) and P(X = k).

Mike is looking for a loan. He is willing to pay no more than an effective rate of 8.000% annually. Which, if any, of the following loans meet Mike’s criteria?Loan X: 7.815% nominal rate, compounded semiannually
Loan Y: 7.724% nominal rate, compounded monthly
Loan Z: 7.698% nominal rate, compounded weekly
a. Y only
b. X and Z
c. Y and Z
d. None of these meet Mike’s criteria.