Describe two human activities that can affect the water cycle.
Answers
consuming the water.... we use up water for drinking and for our homes etc...
hope this helps!
Related Questions
How many moles of carbon are produced when 1745 g of glucose decomposes according to the following equation? C6H12O6 → 6C 6H2O
Help on identifying the solute and solvent
Which changes of state result in a decrease in the kinetic energy of the particles?
An isotope undergoes radioactive decay by emitting radiation that has no mass. What other characteristic does the radiation have?a. some shielding required b. positive or negative charge c. low penetrating power d. no charge
b. air pollution
c. fertilizer use
d. none of the above
Answers
Meat contamination because humans do not eat air or fertilizer so meat contamination is the only logical answer.
- - Answer: A
Answers
SO2 (g) → S (s) + O2 (g) ΔH = +296.8 kJ
2H2 (g) + O2 (g) → 2H2O (g) ΔH = –285.8 kJ
Answers
b. Solutions, colloids, suspensions
c. Colloids, solutions, suspensions
d. Colloids, suspensions, solutions
e. Suspensions, colloids, solutions
Answers
0.80 M HCl(aq)?
(1) 3.6 mL (3) 20. mL
(2) 5.6 mL (4) 40. mL
Answers
Answer: 4) 40 ml
Solution :
According to the neutralization law,
where,
= molarity of NaOH solution = 0.30 M
= volume of NaOH solution = ?
= molarity of HCl solution = 0.80 M
= volume of HCl solution = 15 ml
Now put all the given values in the above law, we get the volume of NaOH solution.
Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.
Final answer:
The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.
Explanation:
The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) can be determined using the concept of stoichiometry and the balanced equation for the reaction between NaOH and HCl. The balanced equation is:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, the number of moles of HCl in 15.0 milliliters of 0.80 M HCl solution can be calculated as:
Moles of HCl = Volume (in liters) × Molarity = 0.015 liters × 0.80 moles/liter = 0.012 moles
Since 1 mole of NaOH reacts with 1 mole of HCl, we need 0.012 moles of NaOH. The volume of 0.30 M NaOH solution can be determined by rearranging the equation:
Volume (in liters) = Moles / Molarity = 0.012 moles / 0.30 moles/liter = 0.04 liters = 40 milliliters
Therefore, the volume of 0.30 M NaOH(aq) needed to completely neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.
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Answers
Answer : The elements include in group 5A are, Nitrogen, phosphorous, arsenic, antimony and bismuth.
Explanation :
According to the modern periodic table, the group 5A is known as group 15. And it is also known as nitrogen family.
The elements present in group 5A are, nitrogen (N), phosphorous (P), arsenic(As), antimony(Sb) and bismuth (Bi).
The general electronic configuration of group 5A elements is,
The number of valance electrons present in group 5A elements are, 5
Hence, the elements include in group 5A are, Nitrogen, phosphorous, arsenic, antimony and bismuth.
Final answer:
Group 5A, also called Group 15 in the modern IUPAC system, contains the elements Nitrogen, Phosphorus, Arsenic, Antimony, Bismuth, and the synthetic element Moscovium. Each of these elements has a p3 configuration in their valence shell.
Explanation:
The elements present in Group 5A (Group 15 in IUPAC system) are known as the pnictogens. This group includes Nitrogen (N), Phosphorus (P), Arsenic (As), Antimony (Sb), Bismuth (Bi) and the unconfirmed synthetic element Moscovium (Mc). These elements, each with a p3 configuration in their valence shell, form compounds with a wide range of properties and uses.
Nitrogen is a common gas in the Earth's atmosphere, deeply involved in biological processes. Phosphorus is key in DNA and energy processes in living beings. Arsenic, Antimony, and Bismuth are metalloids used in various industrial applications. Moscovium is a synthetic element not found naturally and its properties are being studied.
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