Choose values for a and b and use them to verify the product shown.(5a + b)(a – 6b) = 5a2 – 29ab – 6b2

Answers

Answer 1

Answer: just make a=2 and b=3
(5(2)+3)(2-6(3))=5(2)^2-29(2)(3)-6(3)^2
(10+3)(2-18)=5(4)-29(6)-6(9)
(13)(-16)=20-174-54
-208=-208
correct

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The lateral faces of a regular triangular prism are _____.isosceles triangles
equilateral triangles
parallelograms
rectangles

Answers

The lateral face of a prism is it's side, so it would be rectangle, D.

"lateral, of, at, toward, or from the side or sides."

The lateral side of a triangular prism would be a rectangle, like in this picture.
The picture shows two quadrilateral triangles as the faces of the prism, and three rectangles as the lateral sides.

Answer: parallelograms.

Step-by-step explanation:

The lesson states that the lateral faces of a prism are parallelograms.

Given f(x) = —x^2 - 13, find f(-6)

Answers

Answer:

f(-6) = -49

Step-by-step explanation:

f(-6) = -(-6)^2 - 13 = -(36) - 13 = -49.

f(-6)= -49

( f-(-6)= -(-6)^2-13= -(36)-13=-49 )

In Triangle ABC, which trigonometric ratio has the value a/c?A) tan A
B) cos A
C) tan C
D) cos C
E) sin C

Answers

The answer would be A) tan A, because of SOHCAHTOA (if you don't know this, it means SOH) sin=opposite/hypotenuse, CAH) cos=adjacent/hypotenuse, and TOA) tan=opposite/adjacent).

we know that

In the right triangle ABC

$sin(A)=(BC)/(AC)= (a)/(b)$

$cos(A)=(AB)/(AC)= (c)/(b)$

$tan(A)=(BC)/(AB)= (a)/(c)$

$sin(C)=(AB)/(AC)= (c)/(b)$

$cos(C)=(BC)/(AC)= (a)/(b)$

$tan(C)=(AB)/(BC)= (c)/(a)$

therefore

the answer is the option A

$tan(A)$

choose the equation below that represents the line that passes through the point (−2, −1) and has a slope of 5. (5 points) y − 1 = 5(x − 2) y 1 = 5(x 2) y 2 = 5(x 1) y − 2 = 5(x − 1)