Answer:
Therefore either a:b = 5:4 or a:b=-5:4
Step-by-step explanation:
ax²-5bx+4a=0
Since the quadratic equation has two real root.
Then b²-4ac>0
Here a= a , b= -5b and c=4a
∴(-5b)²-4.a.4a=0
⇔25b²=16a²
⇔5b=±4a
Therefore either a:b = 5:4 or a:b=-5:4
14 units
15 units
16 units
17 units
By applying Pythagorean' theorem, the length of ZY to be tangent to circle X is equal to: B. 15 units.
Since line ZY is tangent at point Y and the radius of a circle is always perpendicular to tangents, we can deduce the following points:
Thus, the length of XZ is given by:
XZ = 8 + 9
XZ = 17 units.
Next, we would apply Pythagorean' theorem to find the required length of ZY:
XZ² = ZY² + XX²
17² = ZY² + 8²
ZY² = 289 - 64
ZY = √225
ZY = 15 units.
Read more on Pythagorean theorem here: brainly.com/question/23200848
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Answer:
i believe it is 15
Step-by-step explanation:
Circle X is shown. Line segment X Y is a radius. Line segment Y Z is a tangent that intersects the circle at point Y. A line is drawn from point Z to point X and goes through a point on the circle. The length of the line segment from point X to the point on the circle is 8, and the length of the line segment from the point on the circle to point Z is 9.
What must be the length of ZY in order for ZY to be tangent to circle X at point Y?
14 units
15 units should be 15 units
16 units NOT
17 units
B) 2x2 - 7x - 3
C) 2x2 - 5x - 3
D) 2x2 + 5x - 3
first person to answer is the brainiest
Answer:
The correct option is option D) 2x² + 5x - 3
Step-by-step explanation:
Simplify the expression: (x + 3)(2x - 1)
A) 7x2 - 3
B) 2x2 - 7x - 3
C) 2x2 - 5x - 3
D) 2x2 + 5x - 3
To solve the problem given, we will follow the steps below;
(x + 3)(2x-1)
We will start by opening the parenthesis
x(2x -1) +3(2x-1)
2x² - x + 6x -3
Then we can now add the values with the same coefficient
2x² + 5x -3
Therefore, the correct option is option D) 2x² + 5x - 3
1) 4(x-6)<2
2) 7n+19<8
3) 3(11+x)>=15
4) 4n-12<6
5) 2n+14>=1
6) 2(x+7)>=10
7) 11n-3>9
8)8x+4<=13
9)5n+16>=9
10) 4(x+2)<14
y = 2x
B.
y = x – 2
C.
y = 2x + 2
D.
y = x + 2